The trick is to realize what your choices are.
if m or n or both are divisible by 5, then 2mn will be divisible by 5
I don't know if you know about x mod(5), but in that case there can only be 4 possibilities for m and n
m mod (5) = +/- 2 or m mod(5) = +/- 1
In the first case m^2 = 4 mod(5) and in the second case m^2 = 1 mod(5) N has the same considerations.
If m and n have the same modular results (both are [say] 2 ) then m^2 - n^2 which be 0
If they are different, then (m^2 + n^2) mod 5 = 0
X23 yo mama do ya own work
Answer:
2x
Step-by-step explanation:
is the correct answer so u write it only
<u>Answer:
</u>
One number is 10 more than twice another.Their sum is 1.The numbers are -3 and 4
<u>Solution:
</u>
Given that one number is 10 more than twice the other.
Let us consider the two numbers as “x” and “y”
First number = x
Second number = y
From question, consider “y” is 10 more than twice the “x”. This can be represented
y = 10 + 2x – eqn 1
given that the sum of numbers is 1. Hence we get
x + y =1
substituting the value of “y” we get
x + 10 +2x = 1
3x +10 = 1
3x = -9
x = -3
substitute x = -3 in eqn 1 to get the value of “y”
y = 10 +2(-3)
y=10 – 6 = 4
hence the two numbers are -3 and 4
