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VMariaS [17]
3 years ago
7

What is the best approximation for the perimeter of a semicircle with a dimeter of 12cm?

Mathematics
1 answer:
taurus [48]3 years ago
6 0
Answer is choice B: the circumference of a circle is the same as perimeter and is defined by πd (or pi times diameter) We can cut this in half because we are working with a semicircle: so we have 6π which approximates to the value in answer when using 3.14 for pi Woops: forgot to add the diameter of 12 so we would have 30.84
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Show calculations for each of the ratio table
Sladkaya [172]

Answer:

From left to right:

3, 30, 20

Step-by-step explanation:

Start by determining the ratio of yellow to red paint. Use the column where both amounts are given:

yellow to red = 2 to 6 = 1 to 3

2 to 6 the same as 1 to 3 when reduced, by dividing both sides by 2.

This means yellow paint is a third of red paint. Backwards, red paint is three times yellow paint.

To go from yellow to red, do yellow X 3.

To go from red to yellow, do red ÷ 3.

Column 1:

1 X 3 = 3

Column 3:

10 X 3 = 30

Column 4:

60 ÷ 3 = 20

The ratios are:

1 to 3

2 to 6

10 to 30

20 to 60

4 0
3 years ago
Mike wants to fence in part of his backyard. He wants the length of the fenced-in area to be at least 20 feet long, l ≥ 20. He h
zhuklara [117]

I added a screenshot of the complete question along with the given choices.

<em><u>Answers:</u></em>

w = 10 ft and l = 50 ft ................> second option

w = 20 ft and l = 60 ft ...............> third option

w = 50 ft and l = 40 ft ...............> fifth option

<em><u>Explanation:</u></em>

<u>We are given that:</u>

length should be at least 20 ...........> length ≥ 20

equation for perimeter is : 2l + 2w ≤ 200

<u>We will check each option as follows:</u>

<u>Option 1:</u>

w = 50 ft and l = 10 ft

This option is incorrect as the proposed length is less than 20.

<u>Option 2:</u>

w = 10 ft and l = 50 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(50) + 2(10) = 100 + 20 = 120 ≤ 200

The second condition is also satisfied.

This option is correct

<u>Option 3:</u>

w = 20 ft and l = 60 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(60) + 2(20) = 120 + 40 = 160 ≤ 200

The second condition is also satisfied.

This option is correct

<u>Option 4:</u>

w = 90 ft and l = 30 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(30) + 2(90) = 60 + 180 = 240 > 200

The second condition is not satisfied.

This option is incorrect

<u>Option 5:</u>

w = 50 ft and l = 40 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(50) + 2(40) = 100 + 80 = 180 ≤ 200

The second condition is also satisfied.

This option is correct

Hope this helps :)

8 0
3 years ago
Read 2 more answers
-4x + y = -9<br> -<br> 5x + 2y = 3<br> :<br> Solve the Linear equation
Yuri [45]
-4x+y= -9 can be turned into
y= -9 + 4x

5x+2y=3 (plug y in)
5x+2(-9+4x)=3
5x-18+8x=3
5x+8x=3+18
13x=21
divide 13 on both sides
x=1.6
6 0
2 years ago
What is the distance between parallel lines y=x+3 and y=x+1, rounded to the nearest hundredth?
riadik2000 [5.3K]

Answer:

The distance is 1.41 to nearest hundredth.

Step-by-step explanation:

The line y = x + 3 passes through the point (0, 3) on the yaxis.

Find the perpendicular line passing through this point:

y  - 3 = -1(x + 0)

y = -x + 3

Now find the point where this line intersects the line y = x + 1:

y = -x + 3

y = x + 1

-x + 3 = x  + 1

3 -1 = x + x

2x = 2

x = 1

and y = 2

So this point is (1, 2)

We require the distance between this point and (0, 3)

This = √((3-2)^2 + (0-1)^2) = √2

= 1.4142

3 0
2 years ago
Please help with this its confusing somehow :(​
RoseWind [281]

Answer:

the answer is 7 because 7 *7 is 49

4 0
3 years ago
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