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Sonbull [250]
3 years ago
11

F A taxicab company charges $2.80 plus $0.40 per mile. Carmen paid a fare of $8.80. Enter and solve an equation to find the numb

er of miles she traveled. Use m as your variable.​
Mathematics
2 answers:
lisabon 2012 [21]3 years ago
7 0

Answer:

15 miles

Step-by-step explanation:

8.80-2.80=6

6/0.40=15 miles

zubka84 [21]3 years ago
6 0

m = miles traveled.

$2.80 + $0.40m = $8.80

Subtract $2.80 from both sides.

$0.40m = $6.00

Divide both sides by $0.40

m = 15

Carmen traveled a total of 15 miles.

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Solve a=9y+3xy for y
Sauron [17]

Answer:

y=a/(9+3x)

Step-by-step explanation:

Reverse: 9y+3xy=a

y(9+3x)=a

y=a/(9+3x)

4 0
3 years ago
I need help on 6 -9 use the chart please I need help on it !!!!
natita [175]

Answer:

6 is the first one on the accounting cleark and 9 is 2,500

Step-by-step explanation:

No explanation i just wanted to be nice anhd help you with out anything :)

3 0
3 years ago
Given Sn=2n^2 - 5n, find
brilliants [131]

Answer:

a) -3

b) 117

c) 100

Step-by-step explanation:

(a) 2(1)²-5(1)

1²= 1

2×1= 2

2-5= -3

(b) 2(9)²-5(9)

9²= 81

81×2= 162

162-45= 117

(c) 2(4)²-5(4) +2(8)²-5(4)

4²=16

16×2= 32

32-20= 12

8²=64

64×2= 128

128-40= 88

88+12= 100

hope it helps!

6 0
3 years ago
Ill give brainliest - please help ASAP<br><br> WITH THE WORK THO PLEASE?
ohaa [14]

Answer:

5.

we have.

11x=½(16x+16+50)

22x=16x+66

22x-16x=66

6x=66

x=66/6

x=11

6.

118°=½(6x-11+181)

236=6x+170

6x=236-170

x=66/6

x=11°

7.

34°=½(arcAK-arc LN)

34×2=(110-arc LN)

arc LN =110-68

arc LN=42°

8.

<L=½(arc EN-arc KM)

<L=½(139°-73°)

<L=33

4 0
3 years ago
Suppose a large shipment of microwave ovens contained 12% defectives. If a sample of size 474 is selected, what is the probabili
melisa1 [442]

Answer:

P(\hat p>0.14)

And using the z score given by:

z = \frac{\hat p -\mu_p}{\sigma_p}

Where:

\mu_{\hat p} = 0.12

\sigma_{\hat p}= \sqrt{\frac{0.12*(1-0.12)}{474}}= 0.0149

If we find the z score for \hat p =0.14 we got:

z = \frac{0.14-0.12}{0.0149}= 1.340

So we want to find this probability:

P(z>1.340)

And using the complement rule and the normal standard distribution and excel we got:

P(Z>1.340) = 1-P(Z

Step-by-step explanation:

For this case we have the proportion of interest given p =0.12. And we have a sample size selected n = 474

The distribution of \hat p is given by:

\hat p \sim N (p , \sqrt{\frac{p(1-p)}{n}})

We want to find this probability:

P(\hat p>0.14)

And using the z score given by:

z = \frac{\hat p -\mu_p}{\sigma_p}

Where:

\mu_{\hat p} = 0.12

\sigma_{\hat p}= \sqrt{\frac{0.12*(1-0.12)}{474}}= 0.0149

If we find the z score for \hat p =0.14 we got:

z = \frac{0.14-0.12}{0.0149}= 1.340

So we want to find this probability:

P(z>1.340)

And using the complement rule and the normal standard distribution and excel we got:

P(Z>1.340) = 1-P(Z

4 0
4 years ago
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