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3 years ago

9

Jose ran 2.6 miles. Patel ran 2.60 miles. Who ran farther?

2 answers:

AfilCa [17]3 years ago

7 0

Answer:

Step-by-step explanation:

So they both ran the same distance because is you put 2.6 in money its 2.60 therefore their equal

Verizon [17]3 years ago

5 0

They ran the same amount of miles, because the zero at the end doesn't count.

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What is the slope of the line that passes through the points (4, 10) and (1,10)?

Y_Kistochka [10]

Answer:

0

Step-by-step explanation:

We have two points so we can use the sloe formula

m = (y2-y1)/(x2-x1)

= ( 10-10)/(1-4)

= 0/ -3

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2 years ago

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Find the distance between the points <br><br> a. 3<br> b. 4<br> c. 5<br> d. 6

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Answer:

B. 4

Step-by-step explanation:

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2 years ago

What is 5d=470 and what is 8a=47

Igoryamba

5d=470:

in this case we have to divide both sides by 5:

d=94

8a=47:

in this case we have to divide both sides by 8:

a=5.875

as a general rule, if you want to find out a value of a in
ab=c

you have to divide both sides of the equation by b (if it's not zero); then you will have left:

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3 years ago

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Walnut High Schools Enrollment is exactly five times as large as the enrollment at walmut junior high the total enrollment for t

Vaselesa [24]

Answer:

142

Step-by-step explanation:

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I hope this helps. Cheers^^

6 0

2 years ago

Determine the number of possible solutions for a triangle with B=37 degrees, a=32, b=27

vladimir1956 [14]

Answer:

Two possible solutions

Step-by-step explanation:

we know that

Applying the law of sines

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}$

we have

$a=32\ units$

$b=27\ units$

$B=37\°$

step 1

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}$

substitute the values

$\frac{32}{sin(A)}=\frac{27}{Sin(37\°)}$

$sin(A)=(32)Sin(37\°)/27=0.71326$

$A=arcsin(0.71326)=45.5\°$

The measure of angle A could have two measures

the first measure-------> $A=45.5\°$

the second measure -----> $A=180\°-45.5\°=134.5\°$

step 2

Find the first measure of angle C

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=45.5\°$

$B=37\°$

$45.5\°+37\°+C=180\°$

$C=180\°-(45.5\°+37\°)=97.5\°$

step 3

Find the first length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(97.5\°)}$

$c=Sin(97.5\°)\frac{32}{sin(37\°)}=52.7\ units$

therefore

the measures for the first solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=97.5\°$ , $b=52.7\ units$

step 4

Find the second measure of angle C with the second measure of angle A

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=134.5\°$

$B=37\°$

$134.5\°+37\°+C=180\°$

$C=180\°-(134.5\°+37\°)=8.5\°$

step 5

Find the second length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(8.5\°)}$

$c=Sin(8.5\°)\frac{32}{sin(37\°)}=7.9\ units$

therefore

the measures for the second solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=8.5\°$ , $b=7.9\ units$

6 0

2 years ago