Number 10 please and can you write a equation thanks

Question 2 of 20

nikklg [1K]

Given:

The function on the Input output table.

To find:

The range of the given function.

Solution:

We know that, range is the set of output values.

From the given table it is clear that, hours of training is the input variable and pay per month is the output value.

So, range of the given function is the set of pay per month.

Range = {1100, 1200, 1300, 1400, 1500, 1600, 1700}

Therefore, the correct option is A.

3 0

3 years ago

Mr. Green teaches mathematics and his class recently finished a unit on statistics. The student scores on this unit are: 40 47 5

Harrizon [31]

Answer:

Mean = 64.46, Median = 62 and Mode = Bi-modal (50 and 62)

Range of the data is 55.

Step-by-step explanation:

We are given that Mr. Green teaches mathematics and his class recently finished a unit on statistics.

<u>The student scores on this unit are:</u> 40, 47, 50, 50, 50, 54, 56, 56, 60, 60, 62, 62, 62, 63, 65, 70, 70, 72, 76, 77, 80, 85, 85, 95.

We know that Measures of Central Tendency are: Mean, Median and Mode.

Mean is calculated as;

Mean = $\frac{\sum X}{n}$

where $\sum X$ = Sum of all values in the data

n = Number of observations = 24

So, Mean = $\frac{40+ 47+ 50+ 50+ 50+ 54+ 56+ 56+ 60 +60+ 62+ 62+ 62+ 63+ 65+ 70+ 70+ 72+ 76+ 77+ 80+ 85+ 85+ 95}{24}$

= $\frac{1547}{24}$ = 64.46

So, mean of data si 64.46.

For calculating Median, we have to observe that the number of observations (n) is even or odd, i.e.;

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2})^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}$

Now here in our data, the number of observations is even, i.e. n = 24.

So, Median = $\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}$

= $\frac{(\frac{24}{2})^{th}\text{ obs.} +(\frac{24}{2}+1)^{th}\text{ obs.} }{2}$

= $\frac{(12)^{th}\text{ obs.} +(13)^{th}\text{ obs.} }{2}$

= $\frac{62 + 62 }{2}$ = $\frac{124}{2}$ = 62

Hence, the median of the data is 62.

A Mode is a value that appears maximum number of times in our data.

In our data, there are two values which appear maximum number of times, i.e. 50 and 62 as these both appear maximum 3 times in the data.

This means our data is Bi-modal with 50 and 62.

The Range is calculated as the difference between the highest and lowest value in the data.

Range = Highest value - Lowest value

= 95 - 40 = 55

Hence, range of the data is 55.

5 0

4 years ago

QUESTION 6,7,8 PLS HELP

nevsk [136]

Answer:

6) a.

7) d.

8) a.

I hoped this helped! Please mark me brainliest. Thanks!

8 0

3 years ago

Louise walked from the start of the trail to the bird lookout and back

s344n2d4d5 [400]

Answer:

There is no other information,

Step-by-step explanation:

I do not know what your question is

3 0

3 years ago

Which system is equivalent to 3x squared - 4y squared = 25 over -6x squared -2y squared = 11

TEA [102]

So we are given the following system:
$3x^2-4y^2=25\\
-6x^2-2y^2=11\\\text{Multiply the second equation by -2:}\\12x^2+4y^2=-22\\\text{Add to the first equation we get:}\\15x^2=3
\text{ therefore }x=\pm \sqrt{ \frac{1}{5} }$
Using the first equation again we get:
$3x^2-4y^2=25\\
3x^2=4y^2+25\\
x^2= \frac{1}{3}(4y^2+25)\\x^2= \frac{1}{3}(4 \frac{1}{5} +25)\\= \frac{43}{5}\\x=\pm \sqrt{ \frac{43}{5} }$

3 0

4 years ago