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vladimir2022 [97]
3 years ago
7

If (1, y) is on the graph, then y = ____________ a0.

Mathematics
1 answer:
Debora [2.8K]3 years ago
7 0
If <span>y = -x + 7, and (-1,y) is on the graph, then the following is true:  y=-(-1) + 7, or y=8.

Thus, y = a0 = 8.</span>
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What is the length of ST
Zigmanuir [339]
Take 4.95 and divide it into 2 and you will get ur answer of 2.475 
4 0
3 years ago
Find the number of steel ball bearings, each of diameter 0.7 cm, that can be made from 1kg of steel, given that 1cm cubed of ste
dimulka [17.4K]

Answer:

Ball Bearing Volume = (4 / 3) * PI * radius ^3

Volume = (4 / 3) * 3.14159265 * (.35)^3

Volume = (4 / 3) * 3.14159265 * 0.042875

Volume = 0.17959438 cc

1 cc of steel = 7.8 g

Volume of 1 kg of steel = 1,000 cc / 7.8 g per cc

1 kg = 128.205 cc

Number of ball bearings we can make = 128.205 / 0.17959438

Equals 713.86

Step-by-step explanation:

7 0
3 years ago
Multiply. Just multiply the decimals. Please?
Alex17521 [72]

1) 0.009

2) 0.294

3) 0.0612

4) 33.62

5) 26.46

6) 1.824

5 0
3 years ago
Read 2 more answers
Xavier said the product of a monomial and a binomial will always be a trinomial. Explain the error in his reasoning.
sergejj [24]

All that is needed is a single counter-example.

One counter-example is to multiply the monomial x^3 with the binomial x^7-10x^4

We then get...

x^3*(x^7-10x^4) = x^3*x^7 + x^3*(-10x^4)

x^3*(x^7-10x^4) = x^10 - x^7

The result we get is a binomial as there are still only two terms here. We would need three terms to have a trinomial.

5 0
4 years ago
Read 2 more answers
Find the inequality represented by the graph?
Anon25 [30]

Answer:

y \geqslant  - 2x - 5

Step-by-step explanation:

Since the shaded area is above the line and the line is solid, you will use the greater-than-or-equal-to sign.

Not to mention inequalities still have a slope and y-intercept. (In this case, the y-intercept will be -5, since the line crosses the y-axis at that point, and the slope will be -2 because the line is going down 2 units and to the right 1 unit.)

Hope this helps :)

4 0
2 years ago
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