Answer: 25 in²
Step-by-step explanation: To find the area of a triangle, start with the formula for the area of a triangle which is shown below.
In this problem, we're given that the base is 10 inches
and the height is 5 inches.
Now, plugging into the formula, we have 
.
Now, it doesn't matter which order we multiply.
So we can begin by multiplying (1/2) (10 in.) to get 5 inches.
Now, (5 in.) (5 in.) is 25 in².
So the area of the triangle is 25 in².
Here you'll want to add 5/8 with 5/8. Since they have the same denominator already then 5/8+5/8 = 10/8. Simplifying that down to 5/4 then changing to a mixed number is 1 1/4 inches.
Just do 300x1.4 because that gives you the extra 40% (the answer is £420 btws)
Answer:
72°
Step-by-step explanation:
From the information given:
A town planner wants to build two new streets, Elm Street and Garden Road, to connect parallel streets Maple Drive and Pine Avenue.
We are also told that there is a Trapezoid EFGH with EH as the Pine avenue and EF as the Elm street.
However, side FG and EH are parallel.
∠G = 108°
From the property of parallel lines :
since FG || EH
Then ∠G = ∠H = 108° (i.e corresponding angle will also be equal)
The required angle between Elm Street and Pine Avenue would be interior angles + 180° given that alternate angles are also equal.
The required angle between Elm Street and Pine Avenue = 180° - 108°
The required angle between Elm Street and Pine Avenue = 72°
Answer and Step-by-step explanation:
(a) Given that x and y is even, we want to prove that xy is also even.
For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.
(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:
Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.
(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.
