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Svetlanka [38]
3 years ago
12

31 plz I tried already and got it wrong I don't know how to do it

Mathematics
2 answers:
timurjin [86]3 years ago
7 0
You are to multiply b^4 by b.

You could write this as follows:     "b to the fourth power" times "b to the first power."

Since the bases (b and b) are the same, all you have to do here is to ADD together the two exponents, which are 4 and 1.

Your answer?

inessss [21]3 years ago
3 0
Let's say b equals 2

2^4=16

16*2= 32


This is what I could make of the question
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Y=x(x−2)^3 identify the zeros and their multiplicities.
lawyer [7]
  • The zeros of the function are 0 and 2
  • The multiplicity is the power to which the factors are raised. The multiplicities of the function are 1 and 3.

<h3>Zeros and multiplicities of functions</h3>

Given the function y=x(x-2)^3

The zeros of the function is at the point where y = 0

x(x-2)^3 =0\\x = 0\\(x-2)^3=0\\x-2=0\\x=2

Hence the zeros of the function are 0 and 2

The multiplicity is the power to which the factors are raised. The multiplicities of the function are 1 and 3.

Learn more on zeros and multiplicity here: brainly.com/question/11314797

6 0
3 years ago
A(-1,2) B(3,1) C(1,-4) To the new coordinated A'(-2,4) B'(6,2) C'(2,-8) what was the scale factor?
kicyunya [14]

Answer:

Step-by-step explanation:

A(-1, 2)  ==> A'(-2, 4)

B(3,1) ==> B'(6,2)

C(1,-4) ==> C'(2,-8)

Based on the results of each set, the scale factor is 2

A(-1*2, 2*2)=  A'(-2, 4)

6 0
3 years ago
Can you guys distribute 7(4y+5)=19y+8 and figure out how many solutions this problem has plz and thank you
Alik [6]
It should only have one solution. 
After distributing, you have the equation 
28y + 35 = 19y + 8
Subtract applicable things.
9y = -27
divide both sides by 9.
y = -3

therefore the solution is 
y = -3
6 0
3 years ago
Which figure must be a trapezoid? A. a quadrilateral with exactly one pair of parallel sides.B. a quadrilateral with no congruen
sp2606 [1]
Your Answer is D. but if it's not right i am truly sorry.
6 0
3 years ago
(x+y)² + 2(x+ y)(x- y) + (x– y)²
densk [106]

Answer:

2x(x+y)(x-y)

Step-by-step explanation:

Given the expression;

(x+y)² + 2(x+ y)(x- y) + (x– y)²

Factorize

(x+y)² + (x+ y)(x- y) +   (x+ y)(x- y) + (x– y)²

= (x+y)[x+y+(x-y)] +(x-y)[(x+y)+(x-y)]

= (x+y)(x-y)(x+y+(x-y))

= (x+y)(x-y)(x+y+x-y)

= (x+y)(x-y)(2x)

hence the expanded form is 2x(x+y)(x-y)

6 0
3 years ago
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