- The zeros of the function are 0 and 2
- The multiplicity is the power to which the factors are raised. The multiplicities of the function are 1 and 3.
<h3>Zeros and multiplicities of functions</h3>
Given the function 
The zeros of the function is at the point where y = 0

Hence the zeros of the function are 0 and 2
The multiplicity is the power to which the factors are raised. The multiplicities of the function are 1 and 3.
Learn more on zeros and multiplicity here: brainly.com/question/11314797
Answer:
Step-by-step explanation:
A(-1, 2) ==> A'(-2, 4)
B(3,1) ==> B'(6,2)
C(1,-4) ==> C'(2,-8)
Based on the results of each set, the scale factor is 2
A(-1*2, 2*2)= A'(-2, 4)
It should only have one solution.
After distributing, you have the equation

Subtract applicable things.

divide both sides by 9.

therefore the solution is
Your Answer is D. but if it's not right i am truly sorry.
Answer:
2x(x+y)(x-y)
Step-by-step explanation:
Given the expression;
(x+y)² + 2(x+ y)(x- y) + (x– y)²
Factorize
(x+y)² + (x+ y)(x- y) + (x+ y)(x- y) + (x– y)²
= (x+y)[x+y+(x-y)] +(x-y)[(x+y)+(x-y)]
= (x+y)(x-y)(x+y+(x-y))
= (x+y)(x-y)(x+y+x-y)
= (x+y)(x-y)(2x)
hence the expanded form is 2x(x+y)(x-y)