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krok68 [10]
3 years ago
13

Evaluate the integral by making the given substitution. (use c for the constant of integration.) dt (1 − 8t)3 , u = 1 − 8t

Mathematics
1 answer:
valkas [14]3 years ago
7 0
Here is a solution : 

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A college has a student to teacher ratio of 35 to 2. If there are 180 teachers at the college, how many students attend the coll
Ray Of Light [21]

number of student attend the college are 3150

Step-by-step explanation:

the student teacher ratio is 35:2

let, there are 2x teachers

according to the problem,

2x = 180

or, x = 180/2

= 90

so number of students = 35 X 90 = 3150

7 0
3 years ago
A<br>T<br>R<br>C<br>CR-12 cm<br>RE<br>11<br>TI-<br>IV.<br>VE-<br>CE<br>EA<br>AT​
Afina-wow [57]

Answer:

i think those are cord nits correct me if im wrong i might be

Step-by-step explanation:

5 0
3 years ago
the equation of line t is 6x+5y=3, and the equation of line q is 5x-6y=0. Which statement about the two lines is true?
nekit [7.7K]
The correct answer would be: 6x+5y=3. I am not entirely sure, but that's what I believe is the correct answer.-Hope this helped!
4 0
3 years ago
Jika garis 4x+ay = 8 dan ay=9x + 5 saling tegak lurus,maka nilai a
barxatty [35]

We are given equations as

4x+ay=8

Firstly, we will write in slope intercept form of line

y=mx+b

4x+ay=8

Subtract both sides by 4x

4x+ay-4x=-4x+8

ay=-4x+8

now, we can divide both sides by a

y=-\frac{4}{a} x+\frac{8}{a}

we can find slope

so, we get

m_1=-\frac{4}{a}

we are given second equation as

ay=9x+5

Firstly, we will write in slope intercept form of line

y=mx+b

divide both sides by a

y=\frac{9}{a} +\frac{5}{a}

we can find slope

m_2=\frac{9}{a}

we are given both lines are perpendicular

so, the multiplication of their slopes must  be -1

m_1\times m_2=-1

we can plug values

-\frac{4}{a}\times \frac{9}{a}=-1

now, we can solve for a

\frac{36}{a^2}=-1

Multiply both sides by a

\frac{36}{a^2}\times a^2=1\times a^2

36= a^2

now, we can solve for a

we get

a=-6,a=6...............Answer

4 0
4 years ago
What is the range of the function y = |x |?<br> x ≥ 0<br> y ≥ 0<br> all real numbers
Ivahew [28]
The range is the set of values for y.  Since y=|x|, y is always positive and increases without bound as x approaches +oo.  Thus the range is:

y≥0  which can also be expressed as y=[0, +oo)
6 0
3 years ago
Read 2 more answers
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