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mars1129 [50]
3 years ago
13

© Factorise completely 15z^2-9z -

Mathematics
1 answer:
ollegr [7]3 years ago
4 0

Answer:

3z(5z-3)

Step-by-step explanation:

first you choose the common items which in this case was 3z the you divide 15 by 3 and 9 by 3

You might be interested in
A rectangle has a perimeter of 204 feet. It's length is six feet longer than twice it's width. If L stands for the length of the
Ratling [72]

Answer:

L = 70

W = 32

Step-by-step explanation:

P = 2L + 2W

P 204 feet

W = x

L  = 2x + 6

P = 2L + 2W

P = 2*(2x + 6) + 2*x

P = 4x + 12 + 2x

P = 6x + 12

But we know that P = 204  So 6x + 12 = 204

6x + 12 = 204                    Subtract 12 from both sides

6x + 12 - 12 = 204 - 12       Collect like terms on the right

6x = 192                             Divide by 6

x = 192/6

x = 32

Answer

W = 32

L = 2*W + 6

L = 2*32 + 6

L = 64 + 6

L = 70


7 0
3 years ago
Good Moring please please answers this
ira [324]
The answer will be reflect (2, - 3 ) in x = -1
8 0
3 years ago
What is an algebraic expression for ​"21 more than n​"?
stealth61 [152]

Answer:

Step-by-step explanation:

n+21

3 0
3 years ago
Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a
Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = \frac{1}{6}

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

E(X)=\sum x\cdot P(X=x)

Compute the expected monetary value of a single roll as follows:

E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17

Thus, the expected monetary value of a single roll is $1.17.

7 0
3 years ago
I’m having trouble doing this one can someone finish the rest
kolbaska11 [484]

Answer:

2

Step-by-step explanation:

12-2=m(2+3)

m=10/5=2

m=2

6 0
3 years ago
Read 2 more answers
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