Step-by-step explanation:
1. The equation graph is a parabola, so the maximum height will be the vertex of the parabola. You can find the vertex coordinate t using the formula:
t = -b/2a
t = -18/2•(-4.9)
t = -18/-9.8
t = 1.84 seconds
2. The height of the ground is 0, so the balls hit the ground when the equation result is 0:
0 = -4.9t²+18t+10
Now you solve it using Bhaskara:
Δ = b² -4ac
Δ = 18² -4•(-4.9)•10
Δ = 520
t = (-b ±√Δ)/2a
t = (-18 ± √520)/2•(-4.9)
t1 = (-18 - 20.8)/-9.8
t1 = 3.96 seconds
t2 = (-18 +20.8)/-9.8
t2 = -0.28
Doesn't exist negative time, so we pick the first value found, t = 3.96 seconds
3. Now you just need to put 3 in place of t to find the result:
h = -4.9•3² +18•3 +10
h = -4.9•9 + 54 + 10
h = -44.1 + 64
h = 19.9 meters
4. You just need to put 1 in place of t to find the height:
h = -4.9•1²+12
h = -4.9+12
h = 7.1 meters
Answer:
you can cross multiply or u can 7/20 to get the answer that 7 is 35% of 20
Answer:
the answer should be B -3
Step-by-step explanation:
1+3-5-2= -3
Answer:
nuber 1
Simplifying
3x + 2y = 35
Solving
3x + 2y = 35
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2y' to each side of the equation.
3x + 2y + -2y = 35 + -2y
Combine like terms: 2y + -2y = 0
3x + 0 = 35 + -2y
3x = 35 + -2y
Divide each side by '3'.
x = 11.66666667 + -0.6666666667y
Simplifying
x = 11.66666667 + -0.6666666667y
Answer:
13:30 military time, 1:30 normal time.