Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:length=20/4=5 cmthe ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:AC=4x and BD=3xusing Pythagorean theorem, the length of one side of the rhombus will be:c^2=a^2+b^2substituting our values we get:5²=(2x)²+(1.5x)²25=4x²+2.25x²25=6.25x²x²=4x=2hence the length of the diagonals will be:AC=4x=4×2=8 cmBD=3x=3×2=6 cmHence the area of the rhombus wll be:Area=1/2(AC×BD)=1/2×8×6=24 cm^2
Basically, for this question, all you have to do is make a smaller one and a larger one that is proportional to the original one. The small triangle could be 1/2 of the original, and the enlarged triangle could be double the original. It depends, as long as all of the triangles are proportional to each other.
Well, let's say we start with 10 granola bars.
we take away 3 of them, so there would end up being 7 left.
I assume your teacher is asking for you to write a numerical expression. In this case that would be 10-3=7.
