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FinnZ [79.3K]
3 years ago
12

Help....................................DDDDDDDDDDDDDDDDDDDDDDDDDDD

Mathematics
1 answer:
m_a_m_a [10]3 years ago
8 0

Answer:

Step-by-step explanation:

a). Since, ΔABC ~ ΔWYZ

Their corresponding sides will be proportional.

\frac{AB}{WY}=\frac{BC}{YZ}= \frac{AC}{WZ}

\frac{194}{WY}=\frac{BC}{1}= \frac{130}{WZ}  --------(1)

By applying Pythagoras theorem in ΔABC,

AB² = AC² + BC²

BC² = AB² - AC²

BC² = (194)² - (130)²

BC² = 20736

BC = 144

From equation (1)

\frac{194}{WY}=\frac{144}{1}= \frac{130}{WZ}

\frac{194}{WY}=\frac{144}{1}

WY = \frac{194}{144}

WY = \frac{97}{72} = 1.35

\frac{144}{1}= \frac{130}{WZ}

WZ = \frac{130}{144}

WZ = \frac{65}{72} = 0.90

b). tan(A) = \frac{\text{Opposite side}}{\text{Adjacent side}}

               = \frac{144}{130}

               = \frac{72}{65}

Since, ΔABC ~ ΔWYZ,

∠A ≅ ∠W

Therefore, tangent of angle A and angle W will measure \frac{72}{65}.

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"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries.​ Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).

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