2 | 3
45| 67.5
33| 50
multiplying and dividing by 1.5 based off of the 2-3 ratio.
Answer:
<h2>
$26.25</h2>
<em><u>Solving steps:</u></em>
<em>Question:</em> <u>Sam had some money in his pocket, and he found another $6. 50 in his dresser drawer. He then had a total of $19. 75. Let p represent the amount of money Sam had in his pocket. Which equation can you use to find the amount of money Sam had in his pocket? How much money did Sam have in his pocket?.</u>
<em>Find: </em><em> </em><u>How much money did Sam have in his pocket?.</u>
<em>Solution:</em><em> </em>Let the equation be
<h3><em>=> P = T </em><em>+</em><em>F</em></h3>
<u>p represent amount of money</u>
<u>p represent amount of moneyt represent total</u>
<u>p represent amount of moneyt represent totalf represent money found</u>
<h3>
<em>=> P = T </em><em>+</em><em> </em><em>F</em></h3>
<u>insert the values</u>
<h3><em>=> P = $19.75 </em><em>+</em><em> </em><em>$6.50</em></h3>
add<u> 19.75 from 6.50 </u>
<h3><em>=> P = </em><em> </em><em>26.25</em></h3>
<em><u>THEREFORE THE AMOUNT OF MONEY </u></em><em><u>SAM</u></em><em><u> HAVE IN HIS POCKET</u></em><em><u> IS ABOUT</u></em><em><u> </u></em><em><u> </u></em><em><u>$</u></em><em><u>26.25</u></em>
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:
Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:
Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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1, it is shifted 4 units up
Richelle can fold a hexagon in half and if they match up they will be congruent.
all angles would be congruent
