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Daniel [21]
2 years ago
6

*BRAINLIEST* (EASY QA: Warm UP) Find a positive solution to each equation: x2 = 1/4

Mathematics
2 answers:
Kay [80]2 years ago
6 0

Answer:

C. x = 1/2

Explanation:

\sf \rightarrow x^2 = \dfrac{1}{4}

\sf \rightarrow x=\sqrt{\dfrac{1}{4}},\:x=-\sqrt{\dfrac{1}{4}}

\sf \rightarrow x=\dfrac{1}{2},\:x=-\dfrac{1}{2}

<u>As asked for positive solution (+)</u>

\sf \rightarrrow \sf \rightarrow x=\dfrac{1}{2}

Georgia [21]2 years ago
4 0

\qquad\qquad\huge\underline{{\sf Answer}}

\textbf{Let's get it solved :}

  • \sf{x² = \dfrac{1}{4}}

  • \sf{x = \sqrt{\dfrac{1}{4}}}

  • \sf{x= \pm{\dfrac{1}{2}}}

  • \sf{x ={\dfrac{1}{2}} }

\textsf{[ since we need positive solution ]}

\textsf{Correct choice is C}

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Solve equation x/6+4=15
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x/6+4= 15


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x/6+4-4= 15-4


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2 years ago
2. Choose the graph that shows the solution of the inequality on the number line
horsena [70]

Answer:

Number line 3 also known as [C]

Step-by-step explanation:

<em>Given that:</em>

<em>c ≤ </em>-1

Knowing that:

≤  = Less than or equal to

Now substitute into the equation:

C less than or equal to -1

Thus, it going left on a number line.

The only number line with left is [A] and [C]

Since ≤  = Less than or equal to -1

then, it including -1

also known as a closed circle means the number is included and an open circle means it is not.

Hence, it closed circle.

Thus, the answer is [C]

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4 0
1 year ago
From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many combin
borishaifa [10]

Answer:

495 combinations of 4 students can be selected.

Step-by-step explanation:

The order of the students in the sample is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many combination of random samples of 4 students can be selected?

4 from a set of 12. So

C_{n,x} = \frac{12!}{4!(8)!} = 495

495 combinations of 4 students can be selected.

8 0
3 years ago
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