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Daniel [21]
2 years ago
6

*BRAINLIEST* (EASY QA: Warm UP) Find a positive solution to each equation: x2 = 1/4

Mathematics
2 answers:
Kay [80]2 years ago
6 0

Answer:

C. x = 1/2

Explanation:

\sf \rightarrow x^2 = \dfrac{1}{4}

\sf \rightarrow x=\sqrt{\dfrac{1}{4}},\:x=-\sqrt{\dfrac{1}{4}}

\sf \rightarrow x=\dfrac{1}{2},\:x=-\dfrac{1}{2}

<u>As asked for positive solution (+)</u>

\sf \rightarrrow \sf \rightarrow x=\dfrac{1}{2}

Georgia [21]2 years ago
4 0

\qquad\qquad\huge\underline{{\sf Answer}}

\textbf{Let's get it solved :}

  • \sf{x² = \dfrac{1}{4}}

  • \sf{x = \sqrt{\dfrac{1}{4}}}

  • \sf{x= \pm{\dfrac{1}{2}}}

  • \sf{x ={\dfrac{1}{2}} }

\textsf{[ since we need positive solution ]}

\textsf{Correct choice is C}

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x = 8 ± 2i\sqrt{2}

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3 0
3 years ago
Read 2 more answers
8x+x^2-2y-64+y^2=0 standard form with explanation
xz_007 [3.2K]
X² + 8x +y² - 2y -64 =0
We see that the equation has x² and y² . Also we see that coefficients in front of x² and y² are equal. So this is an equation of the circle.
(x² + 8x) +(y² - 2y) -64 =0
(x² + 8x) +(y² - 2y) = 64
We need to complete square for x and y groups, that means it should be written in form (a+b)² or (a-b)².
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(x² + 2*4x) +(y² - 2*1y) = 64
(x² + 2*4x+4²) +(y² - 2*1y+1²) = 64+4²+1²
(x+4)² + (y-1)²= 81 Sometimes this is called a standard form of the circle.
(x+4)² + (y-1)²= 9² Sometimes it is required to write like this.

And if you are studying circles,ellipses  and hyperbolas, the standard form should look like
\frac{(x+4)^{2}}{9^{2}} + \frac{(y-1)^{2}}{9^{2}} =1






8 0
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