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3 years ago

What is the answer to this 9(-2)=

Mathematics

2 answers:

cestrela7 [59]3 years ago

6 0

The answer is -18

9 · -2 = -18

erastovalidia [21]3 years ago

5 0

9(-2)= - 18 that answer

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Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC

jarptica [38.1K]

We are given

△ABC, m∠A=60° m∠C=45°, AB=8

Firstly, we will find all angles and sides

Calculation of angle B:

we know that sum of all angles is 180

m∠A+ m∠B+m∠C=180

we can plug values

60°+ m∠B+45°=180

m∠B=75°

Calculation of BC:

we can use law of sines

$\frac{AB}{sin(C)}=\frac{BC}{sin(A)}$

now, we can plug values

$\frac{8}{sin(45)}=\frac{BC}{sin(60)}$

$BC=\frac{8}{sin(45)} \times sin(60)$

$BC=9.798$

Calculation of AC:

$\frac{AB}{sin(C)}=\frac{AC}{sin(B)}$

now, we can plug values

$\frac{8}{sin(45)}=\frac{AC}{sin(75)}$

$AC=\frac{8}{sin(45)} \times sin(75)$

$AC=10.928$

Perimeter:

$p=AB+BC+AC$

we can plug values

$p=10.928+8+9.798$

$p=28.726$

Area:

we can use formula

$A=\frac{1}{2}AB \times AC \times sin(A)$

now, we can plug values

$A=\frac{1}{2}8 \times 10.928 \times sin(60)$

$A=37.85570$ ...............Answer

6 0

3 years ago

Read 2 more answers

Can someone help me with the questions in the picture?

OverLord2011 [107]

Answer:

$y = 8$

Step-by-step explanation:

Equation of the line that passes through (-2, 8) with a slope of 0, can be written in point-slope form, $y - y_1 = m(x - x_1)$ and also in slope-intercept form, $y = mx + b$ .

Using a point, (-2, 8) and the slope (m), 0, substitute x1 = -2, y1 = 8 and m = 0 in $y - y_1 = m(x - x_1)$ .

Thus:

$y - 8 = 0(x - (-2))$

$y - 8 = 0$

Rewrite in slope-intercept form

$y - 8 + 8 = 0 + 8$ (addition property of equality)

$y = 8$

8 0

3 years ago

An unknown number b is 10 more than an unknown number k. the number b is also k less than 8. the equations to find k and b are s

Dmitriy789 [7]

Just add the two equations together.
2b = 18
b = 18/2
b = 9

9 = k + 10
9 - 10 = k
k = - 1

6 0

3 years ago

Read 2 more answers

If a cot α = 1 and b cos α = 1, find a2 – b 2

S_A_V [24]

The equivalent expression of the different of two square is -1

Given the following expressions

a cot α = 1

a = 1/cot α = sinα/cosα

b = 1/cos α

We are to find the expression a² - b²

According to difference of two squares;

a² - b² = (a + b) (a - b)

Substitute the given expressions into the formula as shown:

$a^2 - b^2 = (\frac{sin \alpha}{cos \alpha} )^2 - (\frac{1}{cos \alpha} )^2\\a^2 - b^2=\frac{sin^2 \alpha}{cos^2 \alpha} -\frac{1}{cos ^2 \alpha}\\a^2 - b^2=\frac{sin^2 \alpha-1}{cos^2\alpha}\\a^2 - b^2=\frac{-(1-sin^2\alpha)}{cos^2\alpha} \\a^2 - b^2=\frac{-os^2 \alpha}{cos^2 \alpha}\\a^2 - b^2 = -1$

This shows that the equivalent expression of the difference of two squares is -1

Learn more here: brainly.com/question/11084694

4 0

2 years ago

X + y =5 (x + 1)² +(y +1)² =25

algol [13]

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5 0

3 years ago