We find the area of the total square which is 8in • 8in=64in^2 . Now we find the area of the small quadrilateral which is 4in•4in=16 in^2.
Now we subtract the area of the small quadrilateral from the big quadrilateral’s area 64in^2 -16in^2 leaving us with the are of 48in^2 of the figure
Answer:
31/458 or 458/31 you worded it confusingly
Step-by-step explanation:
Answer:
B. 1/16
Step-by-step explanation:
f(-4) = 2^(-4) = 1/(2^4) = 1/16
Answer:
Q
Step-by-step explanation:
The nearest perfect square of sqrt10 is sqrt9 and sqrt 16, representing a 3 and 4.
Thus, we can conclude that sqrt10 is between 3 and 4.
Notice sqrt 10 is very close with sqrt9 than sqrt16, it should be closer to 3 rather than 4.
The only point that fits the context is Q
Look at the picture below!!
If this helped mark me brainliest pls!!
