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3 years ago

The perimeter of a square is 32. What is the area of the square?

1 answer:

3 0

To find the area of the square, take the length times the width, or two of the sides multiplied together. Since the perimeter is 32, the length of each side would be 32/4, because there are four sides in a square.
32/4=8, so each side is 8.

Since the area of a square is the length of the side time the length of a side, the area is 64, because 8 times 8 is 64
Hope this helps!! Can I get Brainliest? It would mean a lot!

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What is the equation of the line with slope of ½ , and which passes through the point (4, - 5)?

Cerrena [4.2K]

Answer:

y = 1/2x - 7

Step-by-step explanation:

y = mx + b

m (slope) = 1/2

x = 4

y = -5

substitute

-5 = 1/2 * 4 + b

-5 = 2 + b

-5 -2 = b

-7 = b

y = mx + b

y = 1/2x -7

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2 years ago

How many meters is a 10 by 3 foot flag?

DENIUS [597]

Answer: 30

Step-by-step explanation:

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3 years ago

Bob can mow 3 lawns in 5 hours. How long would it take it to mow 9 lawns?

olga2289 [7]

Answer:

15 hours

Step-by-step explanation:

9 lawns is 3 times as much as 3 lawns

it will take 3 times as long

3 * 5 hours = 15 hours

3 0

2 years ago

National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a deskt

Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.

Step-by-step explanation:

We are given that National data indicates that 35% of households own a desktop computer.

In a random sample of 570 households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, $H_0$ : p = 25% {means that 35% of households own a desktop computer}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 570 households who owned a desktop computer = 40%

n = sample of households = 570

So, test statistics = $\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }$

= 2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0

3 years ago

salaries of nurses in southern california are normally distributed with a mean of $6250 and a standard deviation of $250. what i

cestrela7 [59]

Step-by-step explanation:

z-score of X = 6150

$\frac{6150 - 6250}{250} = - 0.4 \\$

z-score of X = 6350

$\frac{6350 - 6250}{250} = - 0.4$

P(X<6150) + P(X>6350)

=P(z<-0.4) + P(z>-0.4)

=0.3446+0.3446

=0.6892

3 0

3 years ago