Answer: 
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Work Shown:
6x-y = -3 is the same as 6x-y+3 = 0
6x-y+3 = 0 is the form Ax+By+C = 0 with A = 6, B = -1, C = 3.
The distance d that line is from the point (p,q) = (6, 2) is found by the following
20t^2+9t-20 is the answer
Answer:
30.28 yd²
Step-by-step explanation:
Area enclosed = area of trapezoid + area of semicircle
= ½(a + b)*h + ½(πr²)
Where,
a = 5 yd
b = 2 + 5 = 7 yd
h = 4 yd
r = ½(4) = 2 yd
Plug in the known values
Area enclosed = ½(5 + 7)*4 + ½(π*2²)
Area enclosed = ½(12)*4 + ½(π*4)
= 6*4 + π*2
= 24 + 2π
= 30.2831853
≈ 30.28 yd² (2 decimal places)
Answer:
Step 2
Step-by-step explanation:
Janet replaced 43 from 12 out of nowhere, and there is nothing in the problem indicating that 43 should be changed into 12.
