Answer:
The correct answer is C. The 4th term is 11.
Step-by-step explanation:
Since the next term is one more than twice the previous, we can calculate it by the following expression:
So the second term is:
The third term:
And the fourth term:
The correct answer is C. The 4th term is 11.
Answer:
91
Step-by-step explanation:
This is the answer, I took a pic of the work
<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Answer:
Step-by-step explanation:
<em>y</em> = 10(- 1) - 3 = <em>- 13</em>
<em>y</em> = 10(0) - 3 = <em>- 3 </em>
<em>y</em> = 10(1) - 3 =<em> 7 </em>
<em>y</em> = 10(5) - 3 = <em>47</em>
For this case we must find the solution of the following quadratic equation:
Where:
Then, the solution is given by:
Substituting the values:
By definition we have:
Thus, we have two complex roots.
Answer:
The equation has no real roots.
