Answer: T = 2π√(I/mgD)
Step-by-step explanation:
where:
m is the mass of the pendulum;
I is the moment of inertia of the mass; and
D is the distance from the center of mass to the point of suspension.
Determine the length of the pendulum. For example, it can be equal to 2 m.
Decide a value for the acceleration of gravity. We will use the Earthly figure of 9.80665 m/s², but feel free to check how the pendulum would behave on other planets.
Calculate the period of oscillations according to the formula above: T = 2π√(L/g) = 2π * √(2/9.80665) = 2.837 s.
Find the frequency as the reciprocal of the period: f = 1/T = 0.352 Hz.
You can also let this simple pendulum calculator perform all calculations for you!
Answer: 9-3x
Step-by-step explanation:
You add like terms
don't look at the 3x for now
positive 7 + positive 2 = 9
there is a negative sign next to 3x
9 goes first so
9 - 3x
Answer:
Step-by-step explanation:
(edit):
lol this post was an accident, mb
C3=n
N x 2 - 6 + 2
N < (6x8) - 10
Pythagorean Theorem: a^2 + b^2 = c^2
a = 6
c = 9
b = ?
6^2 + b^2 = 9^2
36 + b^2 = 81
b^2 = 81 - 36
b^2 = 45
b = sqrt(45)
b = 6.71 miles
