Answer:
final concentration: Ca = 0.014 M
Explanation:
Velocity of reaction:
∴ α: order of reaction, assuming α = 1
∴ K = 0.249 s-1.......rate constant
∴ Cao = 0.050 M......initial concentration
∴ t = 5 s.......reaction time
⇒ δCa/δt = K*Ca
⇒ ∫δCa/Ca = K*∫δt
⇒ Ln(Cao/Ca) = K*t = (0.249s-1)(5 s) = 1.245
⇒ Cao/Ca = 3.473
⇒ Ca = 0.050/3.473
⇒ Ca = 0.014 M
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Answer:
Explanation:
Dipole moment = charge x separation of charges
= (2 x 1.6 x 10⁻¹⁹ ) x ( 140 x 10⁻¹² ) coulomb-metre
= 448 x 10⁻³¹coulomb-metre
1 debye = 3.33 x 10⁻³⁰coulomb-metre
Dipole moment in debye = 448 x10⁻³¹ / 3.33 x 10⁻³⁰debye
= 448 x10⁻³¹ / 33.3 x 10⁻³¹
= 13.45 debye
=
......H
......|
H—C—H
..... |
..... H
methane CH4
