Answer:
Option D. T
Explanation:
Enthalpy change (ΔH) is simply the difference between the heat content of the product (Hp) and the heat content of the reactant (Hr). Mathematically, it is expressed as:
Enthalpy change (ΔH) = Heat of product (Hp) – heat of reactant (Hr)
ΔH = Hp – Hr
From the diagram given above, the difference between the heat content of product and the heat content of reactant is T.
Therefore, the enthalpy change of the reaction is T.
Answer:
1) FALSE
2) TRUE
3) FALSE
4) FALSE
5) TRUE
Explanation:
<em>1)</em> The first excited state corresponds to n=3. <em>FALSE. </em>The ground state corresponds to n=1 and first excited state corresponds to n=2.
<em>2)</em> The wavelength of light emitted when the electron drops from n=3 to n=2 is shorter than the wavelength of light emitted if the electron falls from n=3 to n=1. <em>TRUE. </em>As the n=2 state is in a higher energy than n=1, the energy difference between n=2 and n=3 are shorter than differences between n=1 and n=3 states.
<em>3)</em> It takes more energy to ionize the electron from n=3 than it does from the ground state. <em>FALSE. </em>An electron with a high energy will be less-atracted by the nucleus than a electron with a low energy because is farther of it.
<em>4)</em> The wavelength of the light emitted when the electron returns to the ground state from n=3 is larger than the wavelength of light absorbed to go from n=1 to n=3. <em>FALSE. </em>The energy differences in light emitted and light absorbed is the same.
<em>5)</em> The electron is farther from the nucleus on average in the n=3 state than in the ground state. <em>TRUE. </em>According Bohr's model, the greater energy level, the farther from the nucleus it is.
I hope it helps!