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igomit [66]
3 years ago
9

What is 100 to the 3rd power?

Mathematics
1 answer:
AleksAgata [21]3 years ago
4 0
100 * 100 = 10,000.
10,000 * 100 = 1,000,000

100^3 = 1,000,000.
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Ms. Davenport's class studied the changes in temperature in math class as a part of their study of rational numbers.
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Step-by-step explanation:

If it was 6 degrees cooler on Monday than it was on Sunday, but also having Tuesday be 4 degrees warmer than Monday, Wednesday would have to be 2 degrees cooler than Tuesday because it is a number that would comply with the limits  

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Your car's back window is in the shape of a trapezoid with the dimensions shown. The 1616-inch window wiper cleans a part of the
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<span>Semicircle area = circle area / 2 = (pi*r^2)/2 16 in is the radius. Let's call the area of this semicircle s. 3.14*16^2=s

</span><span>Trapezoid area = ((base 1 + base 2) / 2) * h Here, base 1 is 44 and base 2 is 36. The height (h) is 20. Let's call this trapezoid's area t. (44+36)/2 *20 = t
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<span>We can remove the area of the semicircle (that created by the windshield wiper) by subtracting it from the area of the trapezoid. t - s = uncleaned area [(44+36)/2 * 20] - [3.14 * 16^2] = uncleaned area</span>
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Which triangle always has only two sides the same length and one angle that measures 90°? A. acute scalene B. right isosceles C.
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A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In
lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

                        P.Q. = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of males having blood disorder= \frac{250}{1000} = 0.25

\hat p_2 = sample proportion of females having blood disorder = \frac{275}{1000} = 0.275

n_1 = sample of males = 1000

n_2 = sample of females = 1000

p_1 = population proportion of males having blood disorder

p_2 = population proportion of females having blood disorder

<em>Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.</em>

<u>So, 95% confidence interval for the difference between the population proportions, </u><u>(</u>p_1-p_2<u>)</u><u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < {(\hat p_1-\hat p_2)-(p_1-p_2)} < 1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

P( (\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < (p_1-p_2) < (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

<u>95% confidence interval for</u> (p_1-p_2) =

[(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }, (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }]

= [ (0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }, (0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} } ]

 = [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0
3 years ago
send a local little league has a total of 60 players 80% of whom are all right hand how many right-handed players are there
Olin [163]
%10 of 60 = 6
Therefore %80 of 60 = 8*6
= 48.
6 0
3 years ago
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