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nignag [31]
2 years ago
15

A ship's sonar finds that the angle of depression to a wreck on the bottom of the ocean is 15.20. If a point on

Mathematics
1 answer:
Alexxx [7]2 years ago
3 0

Answer:

We have

tan 12.5  = 60 / adj       rearrange  as

adj = 60 / tan 12.5  = about 270.64 m

Step-by-step explanation:

Mark me brainllest

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In a survey of 12 people, it was found that an average of $36 was spent on their child's last birthday gift with a standard devi
Nataliya [291]

Answer:

(27.3692 ; 44.6308)

Step-by-step explanation:

Mean, xbar = 36

Standard deviation, s = 11

Sample size, n = 12

Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718

Confidence interval :

Xbar ± Margin of error

Margin of Error = Tcritical * s/sqrt(n)

Margin of Error = 2.718 * 11/sqrt(12) = 8.6308

Confidence interval :

Lower boundary : 36 - 8.6308 = 27.3692

Upper boundary : 36 + 8.6308 = 44.6308

(27.3692 ; 44.6308)

3 0
3 years ago
-6 + x over 4=-5 what is the value of x
My name is Ann [436]

Answer:x=26

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The temperature at noon on a winter day was 8°C. At midnight, the temperature had dropped 15°C. What was the temperature at midn
Orlov [11]
The correct answer is -7 degrees
6 0
3 years ago
Read 2 more answers
An object is launched straight into the air. The projectile motion of the object can be modeled using h(t) = 96t – 16t2, where t
ratelena [41]

Answer with Step-by-step explanation:

We are given that height of projectile after t seconds is given by

h(t)=96t-16t^2

a.h(t)=144 ft

144=96t-16t^2

16t^2-96t+144=0

t^2-6t+9=0

t^2-3t-3t+9=0

t(t-3)-3(t-3)=0

(t-3)(t-3)=0

t-3=0

t=3

After 3 s, the height of the project will be 144 feet in the air.

b.h(t)=0

96t-16t^2=0

16t(6-t)=0

16t=0\implies t=0

6-t=0\implies t=6

At t=0, the initial position of projectile

At t=6 s , the projectile will hit the ground.

6 0
3 years ago
Evaluate 3z when z=9
zepelin [54]

Answer:

27

Step-by-step explanation:

given value of Z=9

so, 3×9=27

3 0
3 years ago
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