Answer:
A 1/2
Step-by-step explanation:
Ratio of short length to hypotenuse
= cos60
= 1/2
Answer:
The rational number equivalent to 3.24 repeating is 321/99
Step-by-step explanation:
To convert the decimal number to a rational number we can state this number and its multiples of 10, trying to find two number with identical decimal parts:
n=3.24242424...
10n=32.4242424....
100n=324.2424242...
Now, 100n and n have the same decimal part, then by subtracting these numbers we obtain:
100n-n=324.24242424...-3.24242424... = 321
99n = 321
n = 321/99
C is irrational because there is no definite square root for 15 whereas the square root of 36=6
Answer:
a) For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
b) For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
Part a
For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
Part b
For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got: