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Pepsi [2]
3 years ago
6

Shown below is a problem Margaret solved and the steps she used to solve it. Margaret has entered this problem incorrectly. What

misunderstandings does Margaret have? Show your work.
1/2 (64 + 5) - 0.2 (-20 +10)
1/2 (69) - 6
34.5 - 6
28.5


(paper due on 11/5/18
Mathematics
1 answer:
leva [86]3 years ago
7 0

She has distributed the bracket incorrectly

\frac{1}{2}(64 + 5) - 0.2(- 20 + 10)

= \frac{1}{2}(69) - 0.2 (- 10)

=34.5 + 2

= 36.5



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100 points for correct answer
Tems11 [23]

Answer:

\dfrac{x}{3}+\dfrac{3}{y}

Step-by-step explanation:

<u>Given fraction</u>:

\dfrac{xy+9}{3y}

\textsf{Apply the fraction rule} \quad \dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}:

\implies \dfrac{xy}{3y}+\dfrac{9}{3y}

Rewrite 9 as 3 · 3:

\implies \dfrac{xy}{3y}+\dfrac{3 \cdot 3}{3y}

Cancel the common factor y in the first fraction and the common factor 3 in the second fraction:

\implies \dfrac{x\diagup\!\!\!\!y}{3\diagup\!\!\!\!y}+\dfrac{\diagup\!\!\!\!3 \cdot 3}{\diagup\!\!\!\!3y}

\implies \dfrac{x}{3}+\dfrac{3}{y}

7 0
9 months ago
You want to put shingles on the outside walls and solar panel the roof of the barn shown. It costs ​$2.50 for each square meter
Luden [163]

Answer: 975

Step-by-step explanation:

The cost would be 975

3 0
2 years ago
X/3+9=17 simplify your answer
frosja888 [35]
I think the answer might be x=24
8 0
3 years ago
One question please help! Thanks guys in advance!!!
Ede4ka [16]
Y = kx
80 = 16k
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direct variation

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5 0
3 years ago
Assume that the national credit card interest rate is 12.83 percent. A study of 62 college students finds that their average int
meriva

Answer:

b)  95 percent confidence interval for this single-sample t test

[11.64, 16.36]

Step-by-step explanation:

Explanation:-

Given data  a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.

Sample size 'n' =62

sample mean x⁻ = 14  

sample standard deviation 'S' = 9.3

<u>95 percent confidence interval for this single-sample t test</u>

The values are (x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-}+t_{0.05}\frac{S}{\sqrt{n} })  the <u>95 percent confidence interval for the population mean  'μ'</u>

Degrees of freedom γ=n-1=62-1=61

t₀.₀₅ = 1.9996 at 61 degrees of freedom

(14 - 1.9996\frac{9.3}{\sqrt{62} } ,14+1.9996\frac{9.3}{\sqrt{62} })

(14-2.361 , 14 + 2.361)

[(11.64 , 16.36]

<u>Conclusion:-</u>

95 percent confidence interval for this single-sample t test

[11.64, 16.36]

<u></u>

6 0
3 years ago
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