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2 years ago

12

please just help me and give correct answer and not a wrong short answer i need just explanation and please tell me for each ans

wer

1 answer:

ASHA 777 [7]2 years ago

4 0

Answer:

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╲┃◯┃╭┻┻╮╭┻┻╮┃╲╲

╲┃╮┃┃╭╮┃┃╭╮┃┃╲╲

╲┃╯┃┗┻┻┛┗┻┻┻┻╮╲

╲┃◯┃╭╮╰╯┏━━━┳╯╲

╲┃╭┃╰┏┳┳┳┳┓◯┃╲╲

Step-by-step explanation:

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Monica walks 2 miles each day Monday through Friday. She walks 3 miles on Saturday. She does not walk on Sunday. Monica calculat

makvit [3.9K]

Answer:

She is wrong. She would have walked 337 miles after 29 weeks.

Step-by-step explanation:

13x29=337

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2 years ago

Sonji paid $25 for two scarves, which were different prices. When she got home she could not find the receipt. She remembered th

Oksanka [162]

Answer:

$14

Step-by-step explanation:

Make the variables:

x

x + 3

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2x = 22

x = 11

11, 14

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3 years ago

Read 2 more answers

(-4)-(-2)-{(-5)-[(-7)+(-3)-(-8)]}

aleksklad [387]

Answer:

is one

Step-by-step explanation:

its just one i know trust me

7 0

2 years ago

A combination lock uses three numbers between 1 and 78 with repetition, and they must be selected in the correct sequence. whic

Oksana_A [137]

first number and second number and third number = Total

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Since "order" matters, this is a permutation.

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8 0

3 years ago

Read 2 more answers

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

3 years ago