Ask question

Ask question

All categories

3 years ago

8

What is the total amount and the amount of interest earned on $5,000 at 8% for 20 years? Total Amount Interest Amount compounded

annually compounded semiannually compounded quarterly

1 answer:

Lina20 [59]3 years ago

3 0

Answer:

final balance = 24,634.02

compound interest = 19,634.02

Step-by-step explanation:

You might be interested in

You have prizes to reveal! GO

Alik [6]

Answer:

1/19

Step-by-step explanation:

7 0

3 years ago

A system of two linear equations in which the lines are identical is classified as __________.

Luba_88 [7]

Answer:

Step-by-step explanation:

c. consistent and dependent

3 0

3 years ago

Read 2 more answers

Solve for x<br> 2m-nx=x+4

Airida [17]

2m-4 = x+nx switch sides
2m-4 = x (1+n) common factor
2m-4/1+4 = x divide both side by 1-x

6 0

3 years ago

Identify the k-value that makes the relationship shown in the table below proportional.

uysha [10]

Answer:

The value of k that makes the relationship shown in the table below proportional is $\mathbf{\frac{1}{2}}$

Step-by-step explanation:

The relation is proportional if $y=kx \:or\:k=\frac{y}{x}$

Putting values of x and y to find k.

For x =2 and y =1 k is: $k=\frac{y}{x}=\frac{1}{2}$

For x =4 and y =2 k is: $k=\frac{y}{x}=\frac{2}{4} =\frac{1}{2}$

For x =6 and y = 3 k is: $k=\frac{y}{x}=\frac{3}{6} =\frac{1}{2}$

For x = 8 and y = 4 k is: $k=\frac{y}{x}=\frac{4}{8} =\frac{1}{2}$

For x =10 and y = 5 k is: $k=\frac{y}{x}=\frac{5}{10} =\frac{1}{2}$

So, The value of k that makes the relationship shown in the table below proportional is $\mathbf{\frac{1}{2}}$

5 0

3 years ago

Solve the equation. Round to the nearest hundredth. Show work.

Burka [1]

Answer:

$x=-0.75$

Step-by-step explanation:

The given equation is

$4^{-5x-7}=6^{2x-1}$

We take logarithm of both sides to base 10.

$\log(4^{-5x-7})=\log(6^{2x-1})$

$(-5x-7)\log(4)=(2x-1)\log(6)$

We expand the brackets to get;

$-5x\log(4)-7\log(4)=2x\log(6)-\log(6)$

Group similar terms;

$-7\log(4)+\log(6)=2x\log(6)+5x\log(4)$

$-7\log(4)+\log(6)=(2\log(6)+5\log(4))x$

$\frac{-7\log(4)+\log(6)}{(2\log(6)+5\log(4))}=x$

$x=-0.752478$

To the nearest hundredth.

$x=-0.75$

3 0

3 years ago