Answer:
go to inspect and you can find all the answers there
Answer:
537 students
11 days
Step-by-step explanation:
5000
y= -----------------
(1+4999e^-0.8t)
a) after 8 days means t =8
5000
y= -----------------
(1+4999e^-0.8*8)
5000
y= -----------------
(1+4999e^-6.4)
5000
y= -----------------
(1+8.306)
5000
y= -----------------
(9.306)
y =537.28
Rounding to the nearest student
y = 537 students
b) 1/2 the student population means y =2500 (The 5000 is the student population)
5000
2500= -----------------
(1+4999e^-0.8t)
Multiply each side by (1+4999e^-0.8t)
2500 (1+4999e^-0.8t) = 5000
Divide each side by 2500
(1+4999e^-0.8t) = 5000/2500
(1+4999e^-0.8t) = 2
Subtract 1
(4999e^-0.8t) = 2-1
(4999e^-0.8t)=1
Divide by 4999
(4999/4999e^-0.8t)=1/4999
e^-0.8t=1/4999
Take the natural log of each side
ln(e^-0.8t)=ln(1/4999)
-.8t = ln(1/4999)
Divide by -.8
-.8/-8t = -1/.8 *ln(1/4999)
t = -1/.8 *ln(1/4999)
t≈10.6462
Rounding, it will take 11 days
Answer:
B is the answer
Step-by-step explanation:
Answer:
The first step is to find a number that when subtracted from 2 gives you 2.
Step-by-step explanation:
The algebraic part of this problem would be to add the -2 (adding 2 to both sides) to both sides, so
first x-2=2, then x-2(+2)=2(+2) which would give us,
x=4
*note: the parenthesis are just to show that we are adding the 2, to make it more understandable.
