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lukranit [14]
3 years ago
9

What was the amount of the initial deposit that started this savings account?

Mathematics
1 answer:
Nataly_w [17]3 years ago
4 0

Answer:

Step-by-step explanation:

12) The amount of the initial deposit is $1000

13) the slope is (y2 - y1)/(x2 - x1)

Slope = (4000 - 3000)/(6 - 4)

Slope = 1000/2 = 500

The y intercept is the value of y when x is zero. Therefore,

y intercept = 1000.

14) The equation of a straight line represented in the slope intercept form is

y = mx + c

Where

m represents slope

c represents intercept

Therefore the equation is

y = 500x + 1000

15) The slope represents rate of change in the amount saved with respect to time in months.

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How many 1/3-​yard long pieces of wood can be cut from​ 1-yard long piece of​ wood?
never [62]

Answer:

3 pieces

I hope this helps

Step-by-step explanation:

X(1/3) = 1

x/3 = 1

X= 1×3 = 3

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3 years ago
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alekssr [168]

Answer:

The width of the window should be 7.6\ ft and the height of the window should be 3.8\ ft

Step-by-step explanation:

we know that

The circumference of a semicircle (window) is equal to

C=\pi r

we have that

C=12\ ft

\pi=3.14

substitute and solve for r

12=(3.14)r

r=12/3.14=3.8\ ft

so

the width of the window is equal to the diameter of the semicircle

so

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4 0
3 years ago
A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6
katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is 49\ ft

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

h(t)=-16t^{2} +63t+4

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

h(3)=-16(3)^{2} +63(3)+4=49\ ft

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

so

Convert the function into a vertex form

h(t)=-16t^{2} +63t+4

Group terms that contain the same variable, and move the constant to the opposite side of the equation

h(t)-4=-16t^{2} +63t

Factor the leading coefficient

h(t)-4=-16(t^{2} -(63/16)t)

Complete the square. Remember to balance the equation by adding the same constants to each side

h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})

h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})

Rewrite as perfect squares

h(t)-(67,600/1,024)=-16(t-(63/32))^{2}

h(t)=-16(t-(63/32))^{2}+(67,600/1,024)

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

so

h(t)=-16t^{2} +63t+4

For h(t)=0

0=-16t^{2} +63t+4

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

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Answer:

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Step-by-step explanation:

I don't see anything, is there supposed to be anything here? if not

<em>Thank you extra for FREE points! :D</em>

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Answer:

1,260

Step-by-step explanation:


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