Given:
The statement is "two sevenths times four sixths".
To find:
The value of the product.
Solution:
Two sevenths times four sixths can be written as:
It can be rewritten as:
The answer of given expression is eight forty seconds.
Therefore, the correct option is B.
Answer:
The average rate of change over the interval is 120
Step-by-step explanation:
For a function f(x) the average rate of change over an interval [a,b] is given as;
f(b)-f(a)/b-a
in this case, a is 2 and b is 4
f(b) is 256 and f(a) is 16
Substituting these values in the equation for rate of change, we have;
(256-16)/(4-2) = 240/2 = 120
Answer:
for first parallelogram
Area of parallelogram = b*h= 3.5*2= 7square unit
for second parallelogram
Area of parallelogram = b*h = 1.8 square unit
or, 3*h = 1.8
h= o.6unit
For third parallelogram
Area of parallelogram = b*h = 20.4square unit
4*b= 20.4
b=5.1 unit
Step-by-step explanation:
<h2>9.</h2><h3>Given</h3>
<h3>Find</h3>
- linear approximation to the volume when the radius increases 0.4 cm
<h3>Solution</h3>
The equation for volume of a sphere is
... V = (4/3)π·r³
Differentiating gives
... dV = 4π·r²·dr
Filling in the given numbers gives
... change in volume ≈ 4π·(15 cm)²·(0.4 cm)
... = 360π cm³ ≈ 1130.97 cm³ . . . . . . volume of layer 4mm thick
<h2>11.</h2><h3>Given</h3>
- an x by x by 2x cuboid with surface area 129.6 cm²
- rate of change of x is 0.01 cm/s
<h3>Find</h3>
<h3>Solution</h3>
The area is that of two cubes of dimension x joined together. The area of each such cube is 6x², but the two joined faces don't count in the external surface area. Thus the area of the cuboid is 10x².
The volume of the cuboid is that of two cubes joined, so is 2x³. Then the rate of change of volume is
... dV/dt = (d/dt)(2x³) = 6x²·dx/dt
We know x² = A/10, where A is the area of the cuboid, so the rate of change of volume is ...
... dV/dt = (6/10)A·dx/dt = 0.6·(129.6 cm²)(0.01 cm/s)
... dV/dt = 0.7776 cm³/s
