Let
. Then

lies in the second quadrant, so

So we have

and the fourth roots of
are

where
. In particular, they are




The angle of the plane when it rose from the ground is 64.8 degrees
<h3>Application of trigonometry identity</h3>
Given the following parameters from the question
Altitude of the airplane H = 500m
Horizontal distance from airport "d" = 235
Required
angle of elevation
According to the trigonometry identity
tan x = opposite/adjacent
tan x = H/d
tan x = 500/235
tan x = 2.1277
x = arctan(2.1277)
x = 64.8 degrees
The angle of the plane when it rose from the ground is 64.8 degrees
Learn more on angle of elevation here: brainly.com/question/88158
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Answer:
16/25
Step-by-step explanation:
length of screen B=44*(5/4)=55cm
and its width=32*(5/4)=40cm
so, screen B had dimensions 55cm by 40 cm
screen A area=44*32 cm sqr
screen B area=55*40 cm sqr
so, model A screen area/model B screen area
=(44*32)/(55*40)
=16/25
Answer:
(- ∞ , 88)
Step-by-step explanation:
1) m - 88 < - 176
add 88 to both sides
2) m < -88
3) interval notation: ( - ∞, 88)