SOLUTION
From the question, the center of the hyperbola is
a is the distance between the center to vertex, which is -1 or 1, and
c is the distance between the center to foci, which is -2 or 2.
b is given as
![\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%5E2%3Dc%5E2-a%5E2%20%5C%5C%20b%5E2%3D2%5E2-1%5E2%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B3%7D%20%5Cend%7Bgathered%7D)
But equation of a hyperbola is given as
Substituting the values of a, b, h and k, we have
![\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%28x-0%29%5E2%7D%7B1%5E2%7D-%5Cfrac%7B%28y-0%29%5E2%7D%7B%5Csqrt%5B%5D%7B3%7D%5E2%7D%3D1%20%5C%5C%20%5Cfrac%7Bx%5E2%7D%7B1%7D-%5Cfrac%7By%5E2%7D%7B3%7D%3D1%20%5Cend%7Bgathered%7D)
Hence the answer is
Answer:
height of cylinder = 4/3 h
Step-by-step explanation:
The solid has a cylinder surmounted with a cone .Therefore, the volume of the solid is the sum of the cone and the cylinder.
volume of the solid = volume of cylinder + volume of cone
volume of the solid = πr²h + 1/3πr²h
let
height of the cylinder = H
recall
the height of the cone = 2h
volume of the solid = πr²h + 1/3πr²h
3(1/3πr²2h) = πr²H + 1/3πr²2h
2πr²h = πr²H + 2/3 πr²h
πr²(2h) = πr²(H + 2/3 h)
divide both sides by πr²
2h = H + 2/3 h
2h - 2/3h = H
H = 6h - 2h/3
H = 4/3 h
height of cylinder = 4/3 h
Answer:
8
Step-by-step explanation:
4x=32
÷4 ÷4
__________
x=8
Answer:
4 pounds
Step-by-step explanation:
First, I subtracted the cost of the first pound from the final product (3.73 - 2.38) and I got 1.35. I then divided the 1.35 by .45 (the 45 cents) to figure out how many more pounds the package was from the initial 1 pounds. 1.35/.45 is 3, plus the 1 pound from the beginning makes 4 pounds in total.
Answer: I agree with Gloria because 10 times 354.6 is 3546
Step-by-step explanation:
