Can someone explain how to factor a number like in the picture I attached? Thank you!

Mathematics

1 answer:

xenn [34]3 years ago

5 0

hey man im sorry i just need points because im strugling

Step-by-step explanation:

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A grant writer had a taxable income of $37,450 last year. If he paid 10% of his income between $0 and $8350, 15% of his income b

Korvikt [17]

10% of 8350=$835.

15% of 25600(8350 from 33950) =25,600 15% of 25600= 3840.
25% of 3500. (32450 minus 33950= 3500 25% of 3500 =875.

Add the three and you get $5550. Of course you could have eliminated step two and three by anticipating a tax that far exceeded the other choices which were way to low to even consider.
Work this out for yourself. It is simple and fun when you get the hang of it.

Hope This Helped! :3

7 0

3 years ago

Read 2 more answers

CAN SOMEONE HELP ME PLEASE ASAP!?

valentinak56 [21]

Answer:

last option

Step-by-step explanation:

b) 1/6 = 16.7 to 1dp

c) 45% = 45/100 = 9/20

d) 7/9 = 77.8% to 1dp

8 0

3 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

$g(y) = \frac{y-5}{y^2-3y+15}$

According to the quotient rule:

$d(\frac{f(y)}{h(y)}) = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}$

Applying the quotient rule:

$g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}$

The values for which g'(y) are zero are the critical points:

$g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10$