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3 years ago

How many degrees are there in 3pi/2 radians?

1 answer:

5 0

$\displaystyle \\ 
\pi ~ \texttt{radians} = 180^o\\ \\ 
 \frac{3 \pi}{2} ~ \texttt{radians} =\frac{3 \times 180 }{2} = 3 \times 90 = \boxed{ 270^o }$

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What is the result of an increase by 2/3

velikii [3]

Answer:

y=1.6 repeatin

Step-by-step explanation:

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2 years ago

Read 2 more answers

I really don't get it plz help

marshall27 [118]

Answer:

Step-by-step explanation:

Change g(n) to y

y = 2n - 2

2y - 2 = n

2y = n + 2

y = (n + 2)/2

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solution is B

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3 years ago

Apply the distributive property using the greatest common factor to write an equivalent expression. Enter your answers in the bo

Lilit [14]

Solution:

0.3 × 2.7

Using Distributive property of multiplication with respect to subtraction the value of multiplication of two rationals or two decimals

⇒0.3 × (3-0.3)

⇒ 0.3 × 3 - 0.3 × 0.3

⇒ 0.9 - 0.09

= 0.81

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The Equivalent of product of 0.3 × 2.7 are

1.→0.9 × 0.9

2.→→ 3 × 0.27

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3 years ago

Mr Coope drives 472 miles in 8 hours. At this rate, how many miles would he drive in 6

KatRina [158]

8hrs = 480mins
6hrs = 360 mins
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D) 354

6 0

2 years ago

The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m

rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}$

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}$

$\text{Fuel used by 1st auto}=30 \text{ gallons}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}$

$\text{Fuel used by 2nd auto}=20 \text{ gallons}$

Let us find the difference of fuel used by both autos.

$\text{Number of gallons that 2nd auto used less than 1st auto}=30-20$

$\text{Number of gallons that 2nd auto used less than 1st auto}=10$

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces $5\times 10=50$ pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

8 0

2 years ago