All categories

4 years ago

Help a girl out plsss.?

Mathematics

2 answers:

musickatia [10]4 years ago

8 0

The answer is the last one madam :)

Ludmilka [50]4 years ago

4 0

The last one and the first one
hope you got it

You might be interested in

Which statements are true? Check all that apply.<br>

vovikov84 [41]

Answer:

1. It is invisible.

2. It does not emit electromagnetic radiation.

Step-by-step explanation:

got it right on the test

8 0

3 years ago

A garden has the form of a right triangle. One leg of the triangle is formed by a 300-ft long sea wall. The hypotenuse of the tr

lesya [120]

Answer:

27,040,000 = 27,040,000

Step-by-step explanation:

3 0

3 years ago

Plz helppp!!!!! Find the Arc<br> Arc RST

irinina [24]

Answer:

RST: 135°

Step-by-step explanation:

since it's an central angle, its will equal the measure of the central angle

8 0

4 years ago

I NEED HELP PLS THIS IS DUE IN 3 HOURS

Mariulka [41]

Answer:

Part 1) $x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2) $x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

Part 1)

in this problem we have

$x^{2} -2x-2=0$

$a=1\\b=-2\\c=-2$

substitute in the formula

$x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}$

therefore

$x^{2} -2x-2=(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))$

$x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2)

in this problem we have

$x^{2} -6x+4=0$

$a=1\\b=-6\\c=4$

substitute in the formula

$x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(4)}} {2(1)}$

$x=\frac{6(+/-)\sqrt{20}} {2}$

$x=\frac{6(+/-)2\sqrt{5}} {2}$

$x_1=\frac{6(+)2\sqrt{5}}{2}=3+\sqrt{5}$

$x_2=\frac{6(-)2\sqrt{5}}{2}=3-\sqrt{5}$

therefore

$x^{2} -6x+4=(x-(3+\sqrt{5}))(x-(3-\sqrt{5}))$

$x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

5 0

3 years ago

Liono4ka [1.6K]

Answer:

what vfvj u rdjmhgfx Uzumaki i

7 0

3 years ago

Read 2 more answers