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3 years ago

2(w-3)-5w=-3(w+3) , what’s the solution

Mathematics

2 answers:

Olenka [21]3 years ago

6 0

There would be no solution because -6=-9 and thats not equal

8090 [49]3 years ago

3 0

Actually, there would be no solution because the w's cancel out so that leaves -6=-9 and that is not true.

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What is 500-10x80+60 equal??

Sholpan [36]

Answer:

-240

Step-by-step explanation:

500 - 800 + 60

= -300 + 60 = -240

5 0

2 years ago

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The square root of a negative number, such as StartRoot negative 144 EndRoot, is undefined. Explain why the square root of –x, S

IRINA_888 [86]

Answer:

see the explanation

Step-by-step explanation:

we have

$f(x)=\sqrt{-x}$

we know that

The radicand of the function cannot be a negative number

$-x\geq 0$

Solve for x

Multiply by -1 both sides

$x\leq 0$

The domain of the function f(x) is the interval -----> (-∞, 0]

The domain is all real numbers less than or equal to zero

The range of the function f(x) is the interval ----> [0,∞)

The range is all real numbers greater than or equal to zero

Example

For x=144

$144\leq 0$ ----> is not true

This value of x not satisfy the domain

substitute

$f(x)=\sqrt{-144}$ ----> this value is undefined

For x=-144

$-144\leq 0$ ----> is true

This value of x satisfy the domain

substitute

$f(x)=\sqrt{-(-144)}$

$f(x)=\sqrt{144}$ ----> this value is defined

therefore

The function will be undefined for all those values of x that do not belong to the interval of the domain of the function

6 0

2 years ago

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What is the gcf of 39 and 42

natulia [17]

The answer is 3 because it goes into 39 and 42 and 6 doesn't go into 39

3 0

3 years ago

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Write a unit rate word problem. Please include the solution.

yanalaym [24]

Answer:

bob goes 28 miles in 2 hours while traveling to the store. how many miles does he drive per hour. the answer is 14 miles per hour

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2 years ago

Find (a) arc length and (b) Area of a sector.

barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

Formula

$\textsf{Arc length}=r \theta$

$\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta$

$\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}$

Calculation

Given:

$\theta=\dfrac{5 \pi}{8}$
r = 15 cm

$\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}$

$\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}$

5 0

1 year ago