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3 years ago

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Max bought a new speed boat that cost of $33,000. The boat depreciates approximately 18% of its value each year. Write an equati

on to model the decay value of the speed boat.

1 answer:

Natalija [7]3 years ago

7 0

The correct answer is A=33,000(0.82)^t
I know this because I did the work. ;)
Have a great life! ^v^

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Donald has x twenty-dollar bills and 11 ten-dollar bill. How much money does Donald have? Write your answer as an expression.

kirill115 [55]

Answer:

Is there anymore information that is given to this question? Like how much money Donald has in total?

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin

saw5 [17]

Treat $\mathcal C$ as the boundary of the region $\mathcal S$ , where $\mathcal S$ is the part of the surface $z=2xy$ bounded by $\mathcal C$ . We write

$\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r$

with $\mathbf f=(y+7\sin x,z^2+9\cos y,x^3)$ .

By Stoke's theorem, the line integral is equivalent to the surface integral over $\mathcal S$ of the curl of $\mathbf f$ . We have

$\nabla\times\mathbf f=(-2z,-3x^2,-1)$

so the line integral is equivalent to

$\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S$
$=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

where $\mathbf s(u,v)$ is a vector-valued function that parameterizes $\mathcal S$ . In this case, we can take

$\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)$

with $0\le u\le1$ and $0\le v\le2\pi$ . Then

$\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv$

and the integral becomes

$\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv$
$=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi$ <span />

4 0

3 years ago

Write $\frac{99}{100}\cdot(0.\overline{4})$ as a fully simplified fraction.

Oksi-84 [34.3K]

Answer:

$\frac{11}{25}$

Explanation:

The expression that must be rewritten as a fully simplified fraction is:

$\frac{99}{100}\cdot(0.\overline{4})$

You must, first, convert $0.\overline{4}$ as a fraction.

The line over the decimal 4 means that the digit 4 repeats indefinetly.

To find the fraction that represents this number you follow this procedure:

$F=0.\overline 4\\ \\ 10F=4.\overline 4\\ \\ 10F-F=4\\ \\ 9F=4\\ \\ F=4/9$

Now, you can mutiply both fractions:

$\frac{99}{100}.\frac{4}{9}=\frac{99\times 4}{100\times9}=\frac{11}{25}$

6 0

3 years ago

I NEED HELP!!! 21-22

Nesterboy [21]

21. P=118

21. Q=142

22. P=120

22. R=60

22. S=60

3 0

3 years ago

For each trip, a taxi company charges a fixed fee of $2.00 plus $0.75 for each 1/2 mile or fraction of 1/2 miles. If, for every

nydimaria [60]

Answer:

E: 2.00 + 0.75 [ 2r]

Step-by-step explanation:

r represents the number of miles. For each 1/2 mile the taxi will charge and extra free of $0.75. Then, for each mile, the taxi will charge $0.75*2. For example:

For a trip of 1 mile the taxi will charge:

$2.00+$0.75*2

For a trip of 2 miles, the taxi will charge:

$2.00+0.75*4

For a trip of 10 miles, the taxi will charge:

$2.00+$0.75*20

Notice that the variable fee (the one that depends on the number of miles) is $0.75 times the double of miles. In each case the number of miles is multiplied by two. Then the correct answer is E: 2.00 + 0.75 [ 2r]

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3 years ago