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hjlf
3 years ago
14

Max bought a new speed boat that cost of $33,000. The boat depreciates approximately 18% of its value each year. Write an equati

on to model the decay value of the speed boat.
Mathematics
1 answer:
Natalija [7]3 years ago
7 0
The correct answer is A=33,000(0.82)^t
I know this because I did the work. ;)
Have a great life! ^v^
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How do you do number 19
Karo-lina-s [1.5K]
Plug (-6,-5) into the equations to see wich one fits.

y=9/2 x +22
(-5)=9/2(-6) +22
-5=9*-3+22
-5=-27+22
-5=-5

that's how B is the answer. hope this helps :)
7 0
3 years ago
Given: f(-x) = x - 7 and h(x) = 2x + 3
Nitella [24]

Answer:

if given f(-x)=x-7,  then f(h(x))=-2x-10

or  if given f(x)=x-7, then f(h(x))=2x-4

Step-by-step explanation:

if given f(-x)=x-7

f(-x)=x-7 => f(-(-x))=(-x)-7  =>f(x)= -x-7

f(h(x))=f(2x+3)= -(2x+3)-7 = -2x-3-7 = -2x-10

if given f(x)=x-7

f(h(x))=f(2x+3)=2x+3-7=2x-4

6 0
3 years ago
Alfredo has different colored spiral notebooks in his backpack. Which of the following models could be used to simulate a 1 in 3
3241004551 [841]

Answer:

U typed alfredo.. I like alfredo. Alfredo is yum.

Step-by-step explanation:

7 0
3 years ago
Sand is being dumped from a conveyor belt and forms a conical pile. Assuming that the height of this cone is always exactly 3 ti
viva [34]

Answer:

dh/dt =  0.4 m/min

Step-by-step explanation:

The volume of the cone is:

V(c) = (1/3)*r² *h              if always  h = 3r    then    r = h/3

The volume of the cone as a function of h will be:

V(h)  =  (1/3)* (h/3)²*h

V(h) =  (1/27)*h³

The increasing rate of the volume is equal to the rate of sand added the:

D(V)/dt   = (1/27)*3*h²*dh/dt

D(v) / dt  =  10 m³/min

h =  15 m      and   dh/dt is the rate of increasing of the height

By substitution

10 m³/min  = ( 1/9)* 225 * dh/dt  (m²)

dh/dt =  90 / 225   m/min

dh/dt =  0.4 m/min

3 0
3 years ago
Evaluate 2x − 2 for x = 0, x = 1, and x = 2. Question 1 options: A) −1, 0, 2 B) −1, 1, 2 C) 0, 1, 2 D) 1, 2, 4
mixas84 [53]

The value of x in 2^x - 2 when x = 0, x = 1 and x = 2 are -1, 0 and 2 respectively. option A

<h3>Algebra</h3>

2^x - 2

when x = 0

2^x - 2

= 2^0 - 2

= 1 - 2

= -1

when x = 1

2^x - 2

=2^1 - 2

= 2 - 2

= 0

when x = 2

2^x - 2

= 2^2 - 2

= 4 - 2

= 2

Learn more about algebra:

brainly.com/question/4344214

#SPJ1

4 0
2 years ago
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