Answer:
The correct answers are:
Question 4: the first step Keisha should take is: log to the power of x equals log 9.
Question 5: step 4 could be n ln 2 equals ln 86
Question 6: the exact solution is x=ln(7)
Step-by-step explanation:
Ok,
Question 4: the equation that shows the first step Keisha should take is:


(applying the properties of logarithms)

Solution: the first step Keisha should take is: log to the power of x equals log 9.
Question 5: Her first three steps are:

(adding 3 to both sides)



Solution: step 4 is:
(applying the properties of logarithms)
Question 6: The exact solution of 2 e to the power of x equals 14 is:

(dividing both sides by 2)

(ln(e)=1)

Solution: 