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3 years ago

BRAINLIEST ASAP! PLEASE HELP ME :)

Mathematics

1 answer:

mart [117]3 years ago

6 0

I may be wrong, but the numerator breaks up into a product two binomials.

I am joyous to assist you anytime.

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If the spinner is spun 120 times, how many times would you expect it to land on red or orange?

alina1380 [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the value of 2/3^-4

Reptile [31]

Answer:

$\frac{16}{49}$

Step-by-step explanation:

To solve problems like this, we need to multiply the base , $\frac{2}{3}$ , the amount of times as the exponent, 4.

Essentially, the equation is $\frac{2}{3}$ x $\frac{2}{3}$ x $\frac{2}{3}$ x $\frac{2}{3}$ .

The product would be $\frac{16}{49}$ .

Now we can't forget that the exponent is a negative. But because the exponent is an even number, we don't need to worry about that.

Hope this helped :)

8 0

3 years ago

A meter stick casts a shadow 2.4 m long at the same time a flagpole casts a shadow 9.7 m long. How tall is the flagpole

Luda [366]

The first thing we are going to do is draw a diagram of the situation to help us to solve the situation.
We an draw tow similar triangle between the length of the shadows and the height of the stick and the pole.
Since meter stick has a length of 1 meter, the height of our smaller triangle is 1 meter. Let $h$ be height of of the pole. Since both triangles are similiar we can establish a proportion between their corresponding sides and solve for $h$ :
$\frac{h}{1} = \frac{9.7}{2.4}$
$h=\frac{9.7}{2.4}$
$h=4.04$

We can conclude that the pole is 4.04 meters tall.

8 0

3 years ago

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$