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Anna [14]
1 year ago
9

A father and his son decide to sum their age. The sum is equal to sixty years. Six years ago, the age of the father was five tim

es the age of the son. Six years from now the son’s age will be?
Mathematics
2 answers:
arlik [135]1 year ago
5 0

Answer:

20

Step-by-step explanation:

To solve this you have to make a system of equations.

Since the father and son's age sum up to 60, the first equation will be:

f + s = 60

Secondly, since the father's age is 5 times the age of the son 6 years ago the equation will be:

6 - (5s) = f

Now, you have to solve the first equation to let it equal to s

f + s = 60

f = 60 - s

Plug in

6 - 5s = 60 - s

     +s          +s

6 - 4s = 60

-6         -6

---------------------

-4s = 54

-----   -----

 -4     -4

   s ≅ 14

14 + 6 = 20

gregori [183]1 year ago
4 0

Answer:

20.

Step-by-step explanation:

x = father's age and y = son's age,

x + y = 60

x - 6 = 5(y - 6)

x - 5y = -24

Subtract this from first equation:

6y = 84

y = 14

So the son's age is 14.

Six years time son will be 20.

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Step-by-step explanation:

(C). ASA postulate of congruence.

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Step-by-step explanation:

1 .f(x)=x^{2}-x+1

   f(-1)= (-1)-(-1)+1

   f(-1)= 1+1+1

      = 3

3.f(x)=x^{2}-x+1

 f( 1)=(1)-1+1

  f( 1)=1-1+1

        =1

5. f(x)=x^{2}-x+1

    f(3)=(3)^{2}-3+1

         = 9-3+1

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2. g(x) = 5 - 3x

 g( -8)=5-3(-8)

g( -8)=5+24

        =29

4.g(x) = 5 - 3x

g(5)=5-3(5)

 g(5)=5-15

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6.g(x) = 5 - 3x

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3 0
2 years ago
Solve the equations 11(x+10)=132
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11(x+10) = 132

Distributive property

11x + 110 = 132

Now isolate the variable. 

11x + 110 = 132
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132 - 110 = 22

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11x/11 = 22/11
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1. EFG

2. F

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FE and FG does the same thing.

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3 years ago
Max has 5.50. He has eight more quarters than he does nickels. He had four times as many dimes as he has nickels. How many quart
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Answer:

<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>

Step-by-step explanation:

Givens

  • Max has $5.50.
  • He has eight more quarters than he does nickels.
  • He had four times as many dimes as he has nickels.

From these statements, we can deduce algebraical expressions to solve the problem. Let's call q quarters, n nickels and d dimes.

q=n+8 (8 more quarters than nickels)

d=4n (he has four times as many dimes as he has nickels).

0.25q+0.05n+0.10d=5.50 (Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).

Let's replace the first two expressions into the third equation

0.25(n+8)+0.05n+0.10(4n)=5.50\\0.25n+2+0.05n+0.40n=5.50\\0.70n=5.50-2\\n=\frac{3.50}{0.70}\\ n=5

There are 5 nickels.

Now, we use this value to find the number of quarters

q=5+8=13

There are 13 quarters.

Also, d=4(5)=20

There are 20 dimes.

Therefore, there are 13 quarters, 5 nickels and 20 dimes.

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