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Anna [14]
1 year ago
9

A father and his son decide to sum their age. The sum is equal to sixty years. Six years ago, the age of the father was five tim

es the age of the son. Six years from now the son’s age will be?
Mathematics
2 answers:
arlik [135]1 year ago
5 0

Answer:

20

Step-by-step explanation:

To solve this you have to make a system of equations.

Since the father and son's age sum up to 60, the first equation will be:

f + s = 60

Secondly, since the father's age is 5 times the age of the son 6 years ago the equation will be:

6 - (5s) = f

Now, you have to solve the first equation to let it equal to s

f + s = 60

f = 60 - s

Plug in

6 - 5s = 60 - s

     +s          +s

6 - 4s = 60

-6         -6

---------------------

-4s = 54

-----   -----

 -4     -4

   s ≅ 14

14 + 6 = 20

gregori [183]1 year ago
4 0

Answer:

20.

Step-by-step explanation:

x = father's age and y = son's age,

x + y = 60

x - 6 = 5(y - 6)

x - 5y = -24

Subtract this from first equation:

6y = 84

y = 14

So the son's age is 14.

Six years time son will be 20.

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Answer: One plain roll is 4 dollars and one shiny roll is 6 dollars.

Step-by-step explanation:

lets start by saying

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rolls of shiny wrapping paper = y

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Both equations will look like this.

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we can multiply the second equation by -1 to get y alone. (doesn't matter which equation). Once you do that, the positive 4x and the negative 4x cancel out, 3y-2y=1y and 34-28=6. you are left with

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now use that price to find the cost of the plain roll.

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Lets check. Using Kathryn's equation,

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Step-by-step explanation:

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