Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
Answer:
graph shown in image below
Step-by-step explanation:
Answer: 1/12 of a cup
To get this answer, you multiply 1/4 by 1/3
Multiply straight across
(1/4)*(1/3) = (1*1)/(4*3) = 1/12
Pi is approximately 3.14.
Or if you want precision, here's the first 1000 places...
<span>3.14159265358979323846264338327950288419716939937510
58209749445923078164062862089986280348253421170679
82148086513282306647093844609550582231725359408128
48111745028410270193852110555964462294895493038196
44288109756659334461284756482337867831652712019091
45648566923460348610454326648213393607260249141273
72458700660631558817488152092096282925409171536436
78925903600113305305488204665213841469519415116094
33057270365759591953092186117381932611793105118548
07446237996274956735188575272489122793818301194912
98336733624406566430860213949463952247371907021798
60943702770539217176293176752384674818467669405132
00056812714526356082778577134275778960917363717872
14684409012249534301465495853710507922796892589235
42019956112129021960864034418159813629774771309960
51870721134999999837297804995105973173281609631859
50244594553469083026425223082533446850352619311881
71010003137838752886587533208381420617177669147303
59825349042875546873115956286388235378759375195778
18577805321712268066130019278766111959092164201989</span>
Answer:
Step-by-step explanation:
Given that Home sales has 95% confidence interval to estimate the average loss in home value.
a) If std deviation of losses doubles as 3000 from 1500, we have margin of error also increases. Because margin of error
= ±Critical value * Std error
= ±Critical value * Std dev/sqrt n
Hence we find that whenever std deviation increases the margin of error increases, for the same level of confidence.
b) Whenever confidence level increases, critical value increases and as a result margin of error increases. Hence by reducing from 95% to 90% confidence interval would be reduced. True
c) Instead of changing conf level, increasing sample size would give more reliale and accurate results.
