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jeka57 [31]
3 years ago
15

ABCD is a rectangle. Find the length of each diagonal. AC=3y/5 BD=3y-4

Mathematics
2 answers:
motikmotik3 years ago
7 0
Since a rectangle the diagonals AC and BD are congruent. 3y/5 = 3y-4. 3y =15y -20. y=5y-20 -4y=-20 y=5
kipiarov [429]3 years ago
3 0
The diagonals of a rectangle are equal, so

\frac{3y}{5} = 3y-4, then multiply both sides by 5
3y = 5(3y - 4) Distribute the 5
3y = 15y - 20 Subtract 15y from both sides
-12y = -20 Divide both sides by -12
y = \frac{5}{3}

So, AC = \frac{3(5/3)}{5} = 1
and BD = 3(5/3) - 4 = 1
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