Explanation:
The intermediate value theorem (IVT) tells you that for continuous function ...
f(x) = 11^x
if f(1) < 12 and f(2) > 12, then for f(x) = 12, the value of x must be between 1 and 2.
We know f(1) = 11^1 = 11 < 12, and f(2) = 11^2 = 121 > 12, so the conditions are met for the IVT to be applicable.
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In short, the Intermediate Value Theorem says so.
Answer: aggregate or syndicate
Step-by-step explanation:
Answer:
y
=
−
3
x
−
6
Step-by-step explanation:
I hope this helps you
Step-by-step explanation:
Hello there, I think your question missed key information, allow me to add in and hope it will fit the orginal one.
Let assume the side of the cube is a units
=>The surface area of the cude is:
- A =
Given that The bottom of the cake and the area where the two cakes meet is not frosted.
=> the are of a cube that is frosted in the first layer
A' = A -
=
-
=5
=> the are of a cube that is frosted in the second layer
A'' =
-
-
(the bottom and the top of it are not frosted)
= 4
=> the total the area of the cake that is frosted is:
TA = A' + A''
= 5
+ 4
= 9
square units
To solve this type of question, you just need to substitute the actual side of the cube into the expression 9
. Hope it will find you well.