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2 years ago

If cos a=0•8,what is the value of tan a

Mathematics

1 answer:

Alexxandr [17]2 years ago

6 0

Answer:

$\tan( \alpha ) = \frac{ \sqrt{1 - { \cos( \alpha ) }^{2} } }{ \cos( \alpha ) } = \: \frac{ \sqrt{0.36} }{0.8} = \frac{0.6}{0.8}$

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Determine if the side lengths could form a triangle. Use an inequality to prove your answer.

podryga [215]

9514 1404 393

Answer:

a) no

b) yes

c) maybe (no)

Step-by-step explanation:

There are two versions of the triangle inequality. One requires ...

a + b > c

for any triple of side measures a, b, c.

The other allows ...

a + b ≥ c

which admits "triangles" that have zero height and look like line segments.

Most questions asking "do these lengths form a triangle" are concerned with the "greater than" case, and disallow the "or equal to" case.

$16+21=37\ngtr39\qquad\text{not a triangle}$

$27+34=61>58\qquad\text{could be a triangle}$

$9+29=38\ge38\qquad\text{could be a triangle if "equal to" is allowed}$

7 0

2 years ago

Im really stuck on this............

Len [333]

Answer:

H is the Answer

Step-by-step explanation:

Apply distance formula.

$(x {}^{2 } - {x}^{1} ) {}^{2} + ( {y}^{2} - {y}^{1} ) {}^{2} = d {}^{2}$

where d is the distance.

$( - 5 - 7) {}^{2} + (0 - 5) {}^{2} =$

$- 12 {}^{2} + - 5 {}^{2} = {d}^{2}$

$\sqrt{169} = {d}^{2}$

$d = 13$

3 0

2 years ago

Read 2 more answers

4- A manufacturing process produces items whose weights are normally distributed. It is known that 22.57% of all the items produ

galben [10]

Answer:

$\\ \mu = 118\;grams\;and\;\sigma=30\;grams$

Step-by-step explanation:

We need to use z-scores and a standard normal table to find the values that corresponds to the probabilities given, and then to solve a system of equations to find $\\ \mu\;and\;\sigma$ .

<h3>First Case: items from 100 grams to the mean</h3>

For finding probabilities that corresponds to z-scores, we are going to use here a <u>Standard Normal Table </u><u><em>for cumulative probabilities from the mean </em></u><em>(Standard normal table. Cumulative from the mean (0 to Z), 2020, in Wikipedia) </em>that is, the "probability that a statistic is between 0 (the mean) and Z".

A value of a z-score for the probability P(100<x<mean) = 22.57% = 0.2257 corresponds to a value of z-score = 0.6, that is, the value is 0.6 standard deviations from the mean. Since this value is <em>below the mean</em> ("the items produced weigh between 100 grams up to the mean"), then the z-score is negative.

Then

$\\ z = -0.6\;and\;z = \frac{x-\mu}{\sigma}$

$\\ -0.6 = \frac{100-\mu}{\sigma}$ (1)

<h3>Second Case: items from the mean up to 190 grams</h3>

We can apply the same procedure as before. A value of a z-score for the probability P(mean<x<190) = 49.18% = 0.4918 corresponds to a value of z-score = 2.4, which is positive since it is after the mean.

Then

$\\ z =2.4\;and\; z = \frac{x-\mu}{\sigma}$