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3 years ago

13

Solve the literal equation below for y a=9y+2/x

1 answer:

MrRissso [65]3 years ago

3 0

Answer: y = $\frac{ax - 2}{9x}$

Step-by-step explanation: look for the lcm

a= $\frac{9xy + 2}{x}$

cross multiply

ax =9xy + 2

ax - 2 = 9xy

divide both sides by 9x

$\frac{ax - 2}{9x} = \frac{9xy}{9x}$

y= $\frac{ax - 2}{9x}$

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a store is having a sale on chocolate chips and walnuts. for 3 pounds of chocolate chips and 5 pounds of walnuts the total cost

Delvig [45]

If you set you the equations such as 3c+5w=23 and 6c+2w=20 and then solve the first equation for c, you get c= (23-5w)/3 Taking that equation and substituting it for 'c' in the second equation (so the second equation becomes: 6((23-5w)/3)+2w=20 ) you get w=3.25 If you plug that back into your first equation (so it now becomes: 3c+5(3.25)=23 ) you get c=2.25 So the answer would be walnuts cost $3.25 per lb and choc. chips cost $2.25 per lb.

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3 years ago

What is the mode of this data set?

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2 years ago

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vaieri [72.5K]

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3 years ago

Read 2 more answers

The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0

3 years ago

You want to buy a $35,000 car. The company is offering a 3% interest rate for 36 months (3 years). What will your monthly paymen

VikaD [51]

$\bigstar\boxed{\large\bf\purple{\leadsto \$3150}}$

__________________________________________

$\large\sf{\underline{Given:}}$

➠ Principal = $ 35000
➠ Rate of interest = 3%
➠ Time = 3 yrs (36 months)

$\large\sf{\underline{Therefore:}}$

‎‎‎ ‎ ‎‎‎ ‎ ‎ $\sf{Simple\: interest = \left(\dfrac{P\times R\times T}{100}\right)}$

‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\sf{\longrightarrow \left(\dfrac{35000\times 3\times 3}{100}\right)}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\sf{\longrightarrow \cancel{\dfrac{315000}{100}}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎

‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\sf{\longrightarrow 3150}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎

$\large\sf{\underline{Your\: monthly\: payments\:will\:be\:\$3150}}$ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎

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3 years ago