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Colt1911 [192]
3 years ago
10

Bill and Greg are walking in opposite directions with speeds of 45 and 75 feet per minute. When they started, the distance betwe

en them was 20 feet. What will be the distance between them in 2.5 min?
Mathematics
1 answer:
mr_godi [17]3 years ago
3 0
Their distance would be 50 feet in 2.5 minutes, if the speeds remain constant.
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For which values of P and Q does the following equation have infinitely many solutions? Px-37=Qx-37
Lyrx [107]

Answer:

The equation has infinitely many solutions for any value of P and Q such that P=Q.

Step-by-step explanation:

Px - 37 = Qx - 37

Px - Qx - 37 = -37

x (P-Q) = 0

==> P-Q=0 ==> P=Q


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3 years ago
Is there a way to find all the factor pairs for a big number like 805 quickly
Mars2501 [29]

Answer:

The complete list of factors for 805 are 1, 5, 7, 23, 35, 115, 161, and 805.

Step-by-step explanation:

A factor pair is a combination of two factors which can be multiplied together to equal 805. In proper math terms, the number 805 is called the product and the two numbers that can be multiplied together to equal it are called the factors.

In order to work out the factor pairs of 805 we need to first get all of the factors of 805. Once you have the list of all those factors we can pair them together to list out all of the factor pairs.

The complete list of factors for 805 are 1, 5, 7, 23, 35, 115, 161, and 805.

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A blueprint for a building has a scale of 2 inches: 15 feet . One wall on the blueprint measures 8 inches. What is the actual le
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Step-by-step explanation: idk

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In the diagram,MNO is a right angled triangle,Mn=13 cm and MN is 5 cm. Find the value of x​
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Read 2 more answers
Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2
r-ruslan [8.4K]

Answer:

The value of given expression is \frac{21}{128}.

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

q=1-p=1-\frac{1}{2}=\frac{1}{2}

The given expression is

C(n,x)p^xq^{n-x}

It can be written as

^nC_xp^xq^{n-x}

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}

\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}

\frac{7!}{2!5!}(\frac{1}{2})^{2+5}

\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}

21(\frac{1}{2})^{7}

\frac{21}{128}

Therefore the value of given expression is \frac{21}{128}.

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3 years ago
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