Assuming the vertex of the triangle shown is the center of the pentagon, and the line segment shown is an altitude of the triangle:
If we join the center of (the circumscribed circle and of) the pentagon to the 5 vertices, 5 isosceles triangles are formed, all congruent to the one shown in the figure. It is clear that these triangles are congruent, so to find the area of the pentagon, we find the area of one of these triangles and multiply by 5.
The base of the triangle is 22.3 in, and the height is 15.4 ins, thus the area of the pentagon is:
5(Area triangle)=5*[(22.3*15.4)/2]=<span>858.55 (square inches).
Answer: </span>858.55 (square inches).
Answer:
1 - Avenue A is perpendicular to South St.
2 - 70°
Step-by-step explanation:
1 - North, Center, and South St. are parallel lines. Therefore Ave A will be perpendicular to the three lines.
2 - Ave B and Center street forms a 70° angle. Since Center and South St. are parallel lines, they have corresponding angles. Therefore, Ave B and South St also form a 70° angle. The same is true for Ave B and North St.
Answer:
<u>Yes</u>
Step-by-step explanation:
<u>When there are 2 rows</u>
- Number of erasers per row = No. of erasers / No. of rows
- Number of erasers per row = 18/2
- Number of erasers per row = 9
<u>When there are 3 rows</u>
- Number of erasers per row = No. of erasers / No. of rows
- Number of erasers per row = 18/3
- Number of erasers per row = 6
<u>Therefore, there will be more erasers per row in 2 equal rows than in 3 equal rows.</u>
Answer:
polynomial is one. Because the zeros of a polynomial can be determined from the factors of a polynomial, the factors can be created from the zeros. For the zero which occurs at 2, 3 x x = -2/3, the factor which produced that zero is 2. 3 x §· ¨¸ ©¹ The multiplicity represents how many times that zero occurs, in other words, the degree of ...
Step-by-step explanation: