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3 years ago

PLEASE HELP ME ITS ALREADY LATE AND ITS BRINGING MY GRADE WAY DOWN PLEASE HELP ME PLEASE!!!!

Mathematics

1 answer:

Anni [7]3 years ago

3 0

Answer:

I think a=15 and b=9

Step-by-step explanation:

I think that's it could be wrong

there we go ;)

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30 cm

jasenka [17]

Answer:

20 cm i think

Step-by-step explanation:

7 0

4 years ago

It costs $10.99 per month for an online video streaming service. Jackie watched 28 videos in one month. What was the price per v

Kitty [74]

Answer:

Assuming it's actually charging per video, and not just for a subscription, the cost per video would be .40 (40 cents per movie)

Step-by-step explanation:

10.99 / 28 =

.3925

Which rounded up is .40

3 0

4 years ago

The owner of an office building is expanding the length and width of a parking lot by the same amount. The lot currently

nadezda [96]

Answer:

The length of the parking lot should be increased by 20 feet.

Step-by-step explanation:

First, you find the product of 120 and 80, you get 9600.

Next, add 4400 to it. You get 1400

Finally what would you add to both 120 and 80 to get 14000? 20 to get 140*100.

3 0

3 years ago

The vertices A, B, C of a triangle are (2,1),(5,2),and (3,4) respectively . Find the coordinate of the circumcentre and also the

BlackZzzverrR [31]

Answer:

Circumcenter = (4,0)

Circumcircle = √5

Step-by-step explanation:

The circumcentre is the point of intersection of the perpendicular bisectors of a triangle. The vertices of the triangle are equidistant to the circumcentre.

Let us assume the coordinate of the circumcentre is at O(x, y). Therefore the distance between the cirmcumcenter and the vertices are:

$AO=\sqrt{(x-2)^2+(y-1)^2} =\sqrt{x^2-4x+4+(y^2-2y+1)}\\=\sqrt{x^2+y^2-4x-2y+5} \\\\BO=\sqrt{(x-5)^2+(y-2)^2} =\sqrt{x^2-10x+25+(y^2-4y+4)}\\=\sqrt{x^2+y^2-10x-4y+29} \\\\CO=\sqrt{(x-3)^2+(y-4)^2} \\=\sqrt{x^2-9x+9+(y^2-8y+16)}=\sqrt{x^2+y^2-9x-8y+25} \\$

AO = BO, therefore

√(x² + y²-4x-2y+5) = √(x² + y² - 10x - 4y + 29)

x² + y²-4x-2y+5 = x² + y² - 10x - 4y + 29

6x + 2y = 24 (1)

BO = CO

√(x² + y² - 10x - 4y + 29) = √(x² + y² - 9x - 8y + 25)

x² + y² - 10x - 4y + 29 = x² + y² - 9x - 8y + 25

-x + 4y = -4 (2)

Multiply equation 2 by 6 and add to equation 1:

26y = 0

y=0

Put y = 0 in -x + 4y = -4

-x + 4(0) = -4

x = 4

The cicumcenter is at (4, 0)

The radius of the circumcircle = AO = BO = CO. Therefore:

$Radius=AO=\sqrt{(4-2)^2+(0-1)^2} =\sqrt{4+1}=\sqrt{5}$

7 0

3 years ago

A consultant has three sources of income—from teaching short courses, from selling computer software, and from advising on proje

Amanda [17]

Answer:

Mean = $79,000

Standard deviation = $25,000

Step-by-step explanation:

Data provided in the question:

Expected annual incomes:

From teaching short courses = $7,000

From selling computer software = $22,000

From advising on projects = $50,000

Standard deviation:

teaching short courses = $3,000

selling computer software = $4,000

advising on projects = $18,000

Now,

it is given that the events are independent

therefore,

Mean = ∑(Expected annual income)

Mean = $7,000 + $22,000 + $50,000

Mean = $79,000

also,

Standard deviation = ∑(standard deviation)

Standard deviation = $3,000 + $4,000 + $18,000 = $25,000

8 0

3 years ago