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ycow [4]
3 years ago
12

3(x – 2) + 4x = 10(x + 1) ( 25 pts 4 answering right)

Mathematics
2 answers:
pentagon [3]3 years ago
5 0

Answer:

x = -5.33333333

Step-by-step explanation:

Using dist. prop

3x - 6 + 4x = 10x + 10

combine like terms

7x - 6 = 10x + 10

move the 6 over

7x = 10x + 16

move the 10x over

-3x = 16

divide by -3

x = -5.33333333

4vir4ik [10]3 years ago
5 0

Answer:

-16/3

Step-by-step explanation:

3(x-2) + 4x =10(x+1)

Expand brackets

3x -6 +4x = 10x+10

Collect like terms;

3x+4x -6 =10x+10

7x-6= 10x+10

Collect like terms ;

7x-10x = 10+6

-3x = 166

X = -16/3 = - 5 1/3

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(x+3)(x^2-3x+9)

this gets the x^3 while the 3x cancels out and 3*9=27

hope this helps although i didn't explain very well :)
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Artemon [7]
12 for the first one, 6*4=24 24 divided by 2
7 0
3 years ago
-10 x + 4 = 52 x=___ help
Strike441 [17]

Answer: x=-4.8

Step-by-step explanation:

Given

-10x+4=52

Subtract 4 on both sides

-10x+4-4=52-4

-10x=48

Divide -10 on both sides

-10x/-10=48/-10

x=-4.8

Hope this helps!! :)

Please let me know if you have any questions

7 0
3 years ago
Read 2 more answers
Please help mee i dont understand
castortr0y [4]

Answer:

Step-by-step explanation:

(2x-5)(x+6)=0

either 2x-5=0               Or, x+6=0

2x-5=0

2x=0+5

x=5/2

x+6=0

x=0-6

x=-6

so x=5/2 , x=-6

3 0
3 years ago
Read 2 more answers
The ideal width of a safety belt strap for a certain automobile is 6 cm. The actual width can vary by at most 0.45 cm. Write an
OlgaM077 [116]

Answer:

|x-6|\le 0.45

x\in [5.55,6.45]

Step-by-step explanation:

<u>Absolute Value Inequality</u>

Assume the actual width of a safety belt strap for a certain automobile is x. We know the ideal width of the strap is 6 cm. This means the variation from the ideal width is x-6.

Note if x is less than 6, then the variation is negative. We usually don't care about the sign of the variation, just the number. That is why we need to use the absolute value function.

The variation (unsigned) from the ideal width is:

|x-6|

The question requires that the variation is at most 0.45 cm. That poses the inequality:

|x-6|\le 0.45

That is the range of acceptable widths. Let's now solve the inequality.

To solve an inequality for an absolute value less than a positive number N, we write:

-0.45\le x-6 \le 0.45

This is a double inequality than can be easily solved by adding 6 to all the sides.

-0.45+6\le x \le 0.45+6

Operating:

5.55\le x \le 6.45

That is the solution in inequality form. Expressing in interval form:

\boxed{x\in [5.55,6.45]}

3 0
3 years ago
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