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3 years ago

Please help with this question!!?

Mathematics

1 answer:

balu736 [363]3 years ago

8 0

Answer:

6 seconds

Step-by-step explanation:

The ball will hit the ground when its height is 0, so you can plug this into the equation to find your answer.

-16t^2+96t=0

Factoring out -16t, you get:

-16t(t-6), meaning that the solutions are 0 and 6 seconds. Since 0 is the starting point, the answer is 6 seconds. Hope this helps!

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90 points

yan [13]

Answer:

Pythagorean Theorum is defined in Mathematics by a^2 + b^2 = c^2.

One leg (a) is 5. The other leg (b) is 13.

Let's use Pythagorean Theorum.

5^2 + 13^2 = c^2

5 • 5 = 25

13 • 13 = 169

25 + 169 = 194.

Step-by-step explanation:

Hope this helps

5 0

3 years ago

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The locus of points idea allows you to define a circle without giving a numerical value for the radius?

Lunna [17]

The answer would be yes, the locus of points idea allows you to define a circle without giving a numerical value for the radius.

A locus of points is the set of points, and only those points, that satisfies given conditions. The locus of points at a given distance from a given point is a circle whose center is the given point and whose radius is the given distance.

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3 years ago

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Find the six arithmetic means between 1 and 29.

sp2606 [1]

1, ___, ____, _____, _____, _____, ____, 29

29-1 = 28
28/7 = 4
1, 5, 9, 13, 17, 21, 25, 29

7 0

3 years ago

12+3.04+8.28 pls help

vichka [17]

Answer:

23.32

Step-by-step explanation:

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2 years ago

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Quadrilateral RSTU has vertices R(1,3), S(4,1), T(1,-3) and U(-2,-1). Is it true or false that this is a rectangle because the d

Alex777 [14]

Given vertices ofQuadrilateral RSTU as R(1,3), S(4,1), T(1,-3) and U(-2,-1).

We need to check if diagonals are congruent.

The coordinates of verticales diagonal RT are R(1,3) and T(1,-3).

The coordinates of verticales diagonal SU are S(4,1), and U(-2,-1),

By applying distance formula:

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

RT = $=\sqrt{\left(1-1\right)^2+\left(-3-3\right)^2}$ = $\sqrt{36}$

RT = 6

SU $=\sqrt{\left(-2-4\right)^2+\left(-1-1\right)^2}$ .

$=2\sqrt{10}$ .

Diagonal RT is not congruent to Diagonal SU.

Therefore, Quadrilateral RSTU is not a rectangle because the diagonals are not congruent.

So, it is False.

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3 years ago