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2 years ago

Explain why a polar curve is not always bounded

Mathematics

2 answers:

GalinKa [24]2 years ago

8 0

Answer:

vvvvvvvvvv

Step-by-step explanation:

there are lots of common polar curves that are bounded therefore a polar curve is not always bounded all the time. a polar curve is required to have an unbounded function (right side of r = f(θ)) to be an unbounded polar.

nikitadnepr [17]2 years ago

8 0

Answer:

There are lots of common polar curves that are bounded therefore a polar curve is not always bounded all the time. A polar curve is required to have an unbounded function (right side of r = f(θ)) to be an unbounded polar.

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NeTakaya

<h2>Steps:</h2>

So firstly, this function is asking us to divide f(x) by g(x) so let's set that up as such:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\div \frac{x-3}{x+2}$

Next, remember that <u>dividing by a number is the same as multiplying by its reciprocal.</u> To find the reciprocal of a number, flip the numerator and denominator around. With this info, flip the second fraction to it's reciprocal and change the sign to multiplication:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\times \frac{x+2}{x-3}$

Next, we are going to factor x² - x - 6. Firstly, what two terms have a product of -6x² and a sum of -x? That would be -3x and 2x. Replace -x with 2x - 3x:

$(\frac{f}{g})(x)=\frac{x^2+2x-3x-6}{1}\times \frac{x+2}{x-3}$

Next, factor x² + 2x and -3x - 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

$(\frac{f}{g})(x)=\frac{x(x+2)-3(x+2)}{1}\times \frac{x+2}{x-3}$

Now you can rewrite it as:

$(\frac{f}{g})(x)=\frac{(x-3)(x+2)}{1}\times \frac{x+2}{x-3}$

Next, multiply:

$(\frac{f}{g})(x)=\frac{(x-3)(x+2)^2}{x-3}$

Next, divide:

$(\frac{f}{g})(x)=(x+2)^2$

And lastly, simplify:

A good tip: $(x+y)^2=x^2+2xy+y^2$

$(\frac{f}{g})(x)=x^2+4x+4$

<h2>Answer:</h2>

<u>The correct option is C. x² + 4x + 4.</u>

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2 years ago

A lid on a circular container has a diameter of 9 cm. What is the approximate area of the lid? Use 3.14 to approximate pi and ro

kkurt [141]

Area=pir^2

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diameter=9
d/2=9/2=4.5=r

area=pi4.5^2
area=pi20.25
aproxpi=3.14
area=63.585
round hundreth
area=63.59

answer is 63.59cm^2

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Stella [2.4K]

Answer:

Yes they are

Step-by-step explanation:

11(p+q) = 11p + 11q

---------------------------

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