Answer:
Advance tickets=$25
Same-day tickets=$15
Step-by-step explanation:
Complete question below:
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $ 40. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1075 . What was the price of each kind of ticket?
Let
advance tickets=x
Same-day tickets=y
Combined cost of advance and same-day tickets=$40
It means,
x+y=40 Equ (1)
25 advance tickets and 30 same-day tickets=$1075
It means,
25x+30y=1075 Equ(2)
From (1)
x+y=40
x=40-y
Substitute x=40-y into (2)
25x+30y=1075
25(40-y)+30y=1075
1000-25y+30y=1075
5y=1075-1000
5y=75
Divide both sides by 5
5y/5=75/5
y=15
Recall,
x+y=40
x+15=40
x=40-15
=25
x=25
Advance tickets=$25
Same-day tickets=$15
Check
25x+30y=1075
25(25)+30(15)=1075
625+450=1075
1075=1075
Answer:
Y= -3x + 11
Step-by-step explanation:
Y= -3x + 11 (-3x is your slope and 11 is your y intercept)
For this case we have that by definition, the equation in the form of slope-intersection is given by:
Where
Substituting the given point: 
and the cutoff point 
we can find the slope,
We have:
Thus, the equation is given by:
Answer:
See attached image
The answer is -37.
So, let's break this down:
(7 - 10 = -3)
[45 ÷ 3 = 15]
[15 x -3 = -45]
4 x 2 = 8
8 + -45 = -37
Hoped this helped :)
